Q. No.A source \(S_1\) is producing, \(10^{15}\) photons per sec of wavelength \(5000~\mathring{A}.\) Another source \(S_2\) is producing \(1.02\times 10^{15}\) photons per second of wavelength \(5100~\mathring{A}.\) Then the ratio of the power of \(S_2\) to the power of \(S_1\) is equal to:
1.
\(1.00\)
2.
\(1.02\)
3.
\(1.04\)
4.
\(0.98\)
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The potential difference that must be applied to stop the fastest photoelectrons emitted by a nickel surface, having work function 5.01 eV, when ultraviolet light of 200 nm falls on it, must be
1. 2.4 V
2. -1.2 V
3. -2.4 V
4. 1.2 V
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2. 3 X 1016
3. 9 x 1015
4. 3 X 1019
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2. Curves a and b represent incident radiations of the same frequency but of different intensities
3. Curves b and c represent incident radiations of different frequencies and different intensities
4. Curves b and c represent incident radiations of same frequency having the same intensity
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2. threshold frequency (0)
3. intensity of light
4. frequency of light ()
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1. ultraviolet region
2. visible region
3. infrared region
4. X-ray region
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A particle of mass 1 mg has the same wavelength as an electron moving with a velocity of 3 x 106 ms-1. The velocity of the particle is :
(Mass of electron = 9.1 x 10-31 kg)
1.
2.
3.
4.
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1. \(5\times 10^{15}\)
2. \(5\times 10^{16}\)
3. \(5\times 10^{17}\)
4. \(5\times 10^{14}\)
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When photons of energy \(h\nu\) fall on an aluminium plate (of work function \(E_0\)), photoelectrons of maximum kinetic energy \(K\) are ejected.
If the frequency of the radiation is doubled, the maximum kinetic energy of the ejected photoelectrons will be:
1. \(K+ E_0\)
2. \(2K\)
3. \(K\)
4. \(K + h\nu\)
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