Q. No.The mass of a \({}_{3}^{7}\mathrm{Li}\) nucleus is \(0.042\) u less than the sum of the masses of all its nucleons. The binding energy per nucleon of the \({}_{3}^{7}\mathrm{Li}\) nucleus is near:
1. \(4.6\) MeV
2. \(5.6\) MeV
3. \(3.9\) MeV
4. \(23\) MeV
1. \(4.6\) MeV
2. \(5.6\) MeV
3. \(3.9\) MeV
4. \(23\) MeV
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The activity of a radioactive sample is measured as N0 counts per minute at t = 0 and N0/e counts per minute at t = 5 min. The time (in minute) at which the activity reduces to half its value is:
1.
2.
3.
4.
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In the nuclear decay given below:
\({ }_Z^A \mathrm X \rightarrow{ }_{Z+1}^A \mathrm Y \rightarrow{ }_{Z-1}^{A-4} \mathrm B \rightarrow{ }_{Z-1}^{A-4} \mathrm B\)
the particles emitted in the sequence are:
| 1. | \(\beta, \alpha, \gamma \) | 2. | \(\gamma, \beta, \alpha \) |
| 3. | \(\beta, \gamma, \alpha \) | 4. | \(\alpha, \beta, \gamma\) |
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2. Isomer of parent
3. Isotone of parent
4. Isotope of parent
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| 1. | \(M(A, Z)=ZM_p+(A-Z) M_n-B E / c^2\) |
| 2. | \({M}({A}, {Z})={ZM}_{p}+({A}-{Z}) {M}_{n}+{BE}\) |
| 3. | \(M(A, Z)=ZM_p+(A-Z) M_n-B E\) |
| 4. | \({M}({A}, {Z})={ZM}_{p}+({A}-{Z}) {M}_{n}+{BE/c}^2 \) |
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In radioactive decay process, the negatively charged emitted β-particles are:
1. the electrons present inside the nucleus
2. the electrons produced as a result of the decay of neutrons inside the nucleus
3. the electrons produced as a result of collisions between atoms
4. the electrons orbiting around the nucleus
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A nucleus has mass represented by M(A, Z). If Mp and Mn denote the mass of proton and neutron respectively and BE the binding energy, then :
1.
2.
3.
4.
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Two radioactive substances A and B have decay constants 5λ and λ respectively. At t = 0 they have the same number of nuclei. The ratio of the number of nuclei of A to those of B will be after a time interval:
1.
2.
3.
4.
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| 1. | \(25.8\) MeV | 2. | \(23.6\) MeV |
| 3. | \(19.2\) MeV | 4. | \(30.2\) MeV |
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In a radioactive material, the activity at time t1 is R1 and at a later time t2, it is R2. If the decay constant of the material is λ, then:
1.
2.
3.
4.
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