In the reaction Na₂S₂O₃ + 4Cl₂ + 5H₂O → Na₂SO₄ + H₂SO₄ + 8HCI the equivalent weight of Na₂S₂O₃ will be

1. M/4

2. M/8

3. M/1

4. M/2

(M= molecular weight of Na₂S₂O₃)

In the reaction CrO₅ + H₂SO₄ → Cr₂(SO₄)₃ + H₂O + O₂ one mole of CrO₅ will liberate how many moles of O₂

1. 5/2

2. 5/4

3. 9/2

4. none of these

0.4g of a polybasic acid H_nA (all the hydrogens are acidic) requires 0.5g of NaOH for complete neutralization. The number of replaceable hydrogen atoms in the acid and the molecular weight of 'A' would be : (Molecular weight of the acid is 96 gms.)

1. 1, 95

2. 2, 94

3. 3, 93

4. 4, 92

Number of moles of MnO^-₄ required to oxidise one mole of ferrous oxalate completely in acidic medium will be

1. 0.6 mole

2. 0.4 mole

3. 7.5 moles

4. 0.2 mole

One mole of N₂H₄ loses 10 mole of electrons to form a new compound Y. Assuming that all nitrogen appear in the new compound, what is the oxidation state of N₂ in Y ? (There is no change in the oxidation state of hydrogen) 

1. + 3

2. – 3

3. – 1

4. + 5

Consider the change in the oxidation state of Bromine corresponding to different emf values as shown in the diagram below:

\(\small{BrO_4^-\ \overset{1.82V}{\longrightarrow}\ BrO_3^-\ \overset{1.5V}{\longrightarrow} HBrO\ \overset{1.595V}{\longrightarrow}\ Br_2 \overset{1.0652V}{\longrightarrow}\ Br^-}\) 
Then the species undergoing disproportionation is:-

Iron does not get oxidised in:

The respective oxidation states of P in H₄P₂O₅, H₄P₂O₆, and H₄P₂O₇ are: 

On the basis of the following E^O values, the strongest oxidizing agent is 
 ${\left[\mathrm{Fe}{\left(\mathrm{CN}\right)}_6\right]}^{4-}\to {\left[\mathrm{Fe}{\left(\mathrm{CN}\right)}_6\right]}^{3-}+{\mathrm{e}}^{-}; {\mathrm{E}}^{\mathrm{o}}=-0.35 \mathrm{V}$
${\mathrm{Fe}}^{2+}\to {\mathrm{Fe}}^{3+}+{\mathrm{e}}^{-}; {\mathrm{E}}^{\mathrm{o}}=-0.77 \mathrm{V}$
 

1.  ${\left[\mathrm{Fe}{\left(\mathrm{CN}\right)}_6\right]}^{4+}$

2.  ${\mathrm{Fe}}^{2+}$

3.  ${\mathrm{Fe}}^{3+}$

4.  ${\left[\mathrm{Fe}{\left(\mathrm{CN}\right)}_6\right]}^{3-}$