Which is largest in size?

1. Li⁺(aq)

2. Cs⁺(aq)

3. Li⁺(g)

4. Cs⁺(g)

CO₂ gas along with solid (Y) is obtained when sodium salt (X) is heated. (X) is again obtained when CO₂ gas is passed into an aqueous solution (Y). (X) and (Y) can be

1. ${\mathrm{Na}}_2{\mathrm{CO}}_3, {\mathrm{Na}}_2\mathrm{O}$

2. ${\mathrm{Na}}_2{\mathrm{CO}}_3, \mathrm{NaOH}$

3. ${\mathrm{NaHCO}}_3, {\mathrm{Na}}_2{\mathrm{CO}}_3$

4. ${\mathrm{Na}}_2{\mathrm{CO}}_3, {\mathrm{NaHCO}}_3$

A compound which can be used in space vehicles both to absorb CO₂ and liberate O₂ is

$\left(\mathrm{Yellow} \mathrm{ppt}\right)\stackrel{K_{2}Cr{O}_4}{\leftarrow }X\stackrel{dil. HCl}{\to }\left(\mathrm{Yellow} ppt\right)$
$\mathit{+}Z\mathit{\uparrow }\mathit{(}\mathit{p}\mathit{u}\mathit{n}\mathit{g}\mathit{e}\mathit{n}\mathit{t}\mathit{ }\mathit{s}\mathit{m}\mathit{e}\mathit{l}\mathit{l}\mathit{i}\mathit{n}\mathit{g}\mathit{ }\mathit{g}\mathit{a}\mathit{s}\mathit{)}$

If X gives green flame test. Then . X is

1. ${\mathrm{MgSO}}_4$

2. ${\mathrm{BaS}}_2{\mathrm{O}}_3$

3. ${\mathrm{CuSO}}_4$

4. ${\mathrm{PbS}}_2{\mathrm{O}}_3$

The pair of compounds, which cannot exist together in a solution is 

1. ${\mathrm{NaHCO}}_3 \mathrm{and} \mathrm{NaOH}$

2. ${\mathrm{Na}}_2{\mathrm{CO}}_3 \mathrm{and} \mathrm{NaOH}$

3. ${\mathrm{NaHCO}}_3 \mathrm{and} {\mathrm{Na}}_2{\mathrm{CO}}_3$

4. ${\mathrm{NaHCO}}_3 \mathrm{and} {\mathrm{H}}_2\mathrm{O}$

${\mathrm{Mg}}_2{\mathrm{C}}_3+{\mathrm{H}}_2\mathrm{O}\to \mathrm{X} \left(\mathrm{organic} \mathrm{compound}\right)$ compound X is 

1. ${\mathrm{C}}_2{\mathrm{H}}_2$

2. ${\mathrm{CH}}_4$

3. Propyne

4. Ethene

Solution of sodium metal in liquid ammonia 

is a strong reducing agent due to presence of

1. Solvated sodium ions

2. Solvated hydrogen ions

3. Sodium atoms or sodium hydroxide

4. Solvated electrons

The order of solubility of lithium halides in non-polar solvents follows the order

1. LiI > LiBr > LiCl > LiF

2. LiF > LiI > LiBr > LiCl

3. LiCl > LiF > LiI > LiBr

4. LiBr > LiCI > LiF > LiI

Highly pure dilute solution of sodium in ammonia

1. Shows blue colouration due to solvated electrons

2. Shows electrical conductivity due to solvated sodium ions only

3. Shows red colouration due to solvated electrons but a bad 
    conductor of electricity

4. Produces hydrogen gas or carbonate