The half-life of 92U238 against \(\alpha\)-decay is 4.5 × 109 year. The time taken in a year for the decay of the 15/16 part of this isotope will be:
1.
2.
3.
4.
A radioactive isotope has a half-life of 10 day. If today there are 125 g of it left, what was its original weight 40 day earlier?
(1) 600 g
(2) 1000 g
(3) 1250 g
(4) 2000 g
Two radioisotopes P and Q of atomic weight 10 and 20 respectively are mixed in equal amount by weight. After 20 days, their weight ratio is found to be 1:4. Isotope P has a half-life of 10 day. The half-life of isotope Q is:
(1) zero
(2) 5 day
(3) 20 day
(4) infinite
The rate constant of a reaction is . The order of the reaction is :
1. First order
2. Zero order
3. Second order
4. Third order
For a chemical reaction product, the postulated mechanism of the reaction is as follows.
\(E_{a_{1}} = 180 \ kJ \ mol^{-1}, \)
\( E_{a_{2}} = 90 \ kJ \ mol^{-1}, \)
\( E_{a_{3}} = 40 \ kJ \ mol^{-1}\)
then overall activation energy for the reaction given above is
1. 70 kJ mol-1
2. -10 kJ mol-1
3. 310 kJ mol-1
4. 130 kJ mol-1
The activation energy for a simple chemical reaction
A B is Ea in the forward direction.
The activation energy for the reverse reaction:
1. Can be less than or greater than Ea
2. Is always double of Ea
3. Is negative of Ea
4. Is always less than Ea
3A B + C
It would be a zero order reaction when :
(1) The rate of reaction is proportional to square of concentration of A
(2) The rate of reaction remains same at any concentration of A
(3) The rate remains unchanged at any concentration of B and C
(4) The rate of reaction doubles if concentration of B is increased to double.
If the rate of the reaction is equal to the rate constant, the order of the reaction is :
(1) 3
(2) 0
(3) 1
(4) 2
The temperature dependence of rate constant (k) of a chemical reaction is written in terms of Arrhenius equation, k = Ae-Ea/RT . Activation energy Ea of the reaction can be calculated by plotting :
(1) log vs 1 / log T
(2) k vs T
(3) k vs 1 / log T
(4) log k vs 1 / T
The rate constant (in mol L⁻¹ s⁻¹) for a zero-order reaction with an initial concentration of 0.02 M and a half-life of 100 seconds is:
1. \(1.0 \times 10^{-4}\)
2. \(2.0 \times 10^{-4}\)
3. \(2.0 \times 10^{-3}\)
4. \(1.0 \times 10^{-2}\)