the optically active tartaric acid is named as D-(+)- tartaric acid because it has a positive

1.  optical rotation: and is derived from D-glucose

2. pH in an organic solvent

3. optical rotation and is derived from D-(+)-glyceraldehyde

4. optical rotation only when Substituted by deuterium 

The IUPAC name of the above mentioned compound is - 

1. p-Phenyl diphenyl

2. p-1-biphenyl benzene

3.  1,1',4',1''-terphenyl

4. Terphenyl

The total number of optically active isomers for ${\mathrm{CH}}_2\mathrm{OH}{\left(\mathrm{CHOH}\right)}_3\mathrm{CHO}$ are

1.  16

2.  8

3.  4

4.  2

If optical rotation produced by compound (i) is 36$°$ then the rotation produced by compound (ii) is

(i) 

(ii) 

1.  -36$°$

2.  0$°$

3.  +18$°$

4.  +72$°$

The number of the possible open chain (acyclic) isomeric compounds for molecular formula $C_5{H}_{10}$ would be 

1.  5

2.  6

3.  7

4.  4

The IUPAC name of the following compound is

1.  4-hydrazonocyclohexane-1-carboxylic acid

2.  4-hydrazonobenzoic acid

3.  4-hydrazonocyclohexanoic acid

4.  4-(n-amino) benzene carboxylic acid

Consider the following organic compound:

$\stackrel{1}{\mathrm{C}}{\mathrm{H}}_3-\stackrel{2}{\mathrm{C}}{\mathrm{H}}_2—\stackrel{3}{\mathrm{C}}{\mathrm{H}}_2-\stackrel{4}{\mathrm{C}}{\mathrm{H}}_2-\stackrel{5}{\mathrm{C}}{\mathrm{H}}_2-\stackrel{6}{\mathrm{C}}{\mathrm{H}}_2-\stackrel{7}{\mathrm{C}}{\mathrm{H}}_3$

To make it a chiral compound, the attack should be on carbon:

1. 1

2. 4

3. 3

4. 7

Assign the IUPAC name for the following compound.

1. 3, 4-Dichlorobenzene

2. (4-chlorophenyl)(3-chlorophenyl) diazene

3. 3,4-Bis (chlorophenyl) diazene

4. (3-Chlorophenyl)(4-chlorophenyl)diazene

Assign the IUPAC name for the following compound.

1. 3-methyl hexane -1, 2, 3-tricarbonitrile

2. hexane-1, 2, 3-tricarbonitrile

3. 1, 2-bis(cyanomethyl) butanenitrile

4. 3-(cyanomethyl)hexane-1,6-dinitrile

The number of chiral carbon atoms in the given compound is are

1. 2

2. 3

3. 4

4. 1