When 0.1 mole of CH3NH2 (ionization constant Kb=5×10-4) is mixed with 0.08 mol HCl and the volume is made up of 1 litre. The [H+] of resulting solution is -

(log 4 =  0.60)

1. 8×10-2

2. 2×10-11

3. 1.23×10-4

4. 8×10-11

Subtopic:  pH calculation |
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The solution with pH value close to 1.0 among the following is:

1. 100 ml of (M/10) HCl + 100 ml of (M/10) NaOH
2. 55 ml of (M/10) HCl + 45 ml of (M/10) NaOH
3. 10 ml of (M/10) HCl + 90 ml of (M/10) NaOH
4. 85 ml of (M/10) HCl + 15 ml of (M/10) NaOH

Subtopic:  pH calculation |
 61%
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If Ag++2NH3Ag(NH3)2+; K1=1.8×107

Ag++Cl-AgCl; K2=5.6×109

Then for

AgCl+2NH3[Ag(NH3)2]++Cl-,

Equilibrium constant will be

1. 0.32×10-2

2. 3.11×102

2. 10.08×1016

4. 1.00×10-17

Subtopic:  Kp, Kc & Factors Affecting them |
 79%
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Three sparingly soluble salts A2X, AX, and AX3 have the same solubility product. Their solubilities will be in the order:

1. AX3>AX>A2X

2. AX3 < A2X>AX

3. AX>AX3>A2X

4. AX>A2X>AX3

Subtopic:  Solubility Product |
 65%
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Which of the following solution(s) have pH between 6 and 7?

I. 2×10-6 MNaOH

II. 2×10-6 MHCL

III. 10-8 MHCl

IV. 10-13 MNaOH

1. I, II

2. II, III

3. III, IV

4. II, III, IV

Subtopic:  pH calculation |
 59%
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At what pH does Mg(OH)2 start to precipitate from a solution with 0.10 M Mg²⁺ ions, given that the Ksp of Mg(OH)2 is 1 × 10⁻¹¹?

1. 3

2. 6

3. 9

4. 11

Subtopic:  pH calculation |
 71%
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50 litres of 0.1 M HCl are mixed with 50 litres of 0.2 M NaOH. The pH of the resulting solution will be:

1. 12.70

2. 12.34

3. 8.7

4. 4.2

Subtopic:  pH calculation |
 73%
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The pH of a 0.05 M aqueous solution of diethylamine is 12. Its Kb value will be:

1. 2×10-3

2. 2.5×10-3

3. 3×10-3

4. 4.5×10-3

Subtopic:  Ionisation Constant of Acid, Base & Salt |
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Ka for HCN is 5×10-10 at 25°C. For maintaining a constant pH of 9, the volume of 5 M KCN solution required to be added to 10 mL of 2 M HCN solution is-

1. 2 mL

2. 3 mL

3. 4.2 mL

4. 5.6 mL

Subtopic:  Buffer |
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The approximate pH of a solution formed by mixing equal volumes of solutions of 0.1 M sodium propionate and 0.1 M propanoic acid (the dissociation constant of propanoic acid is 1.3×10-5 mol dm-3) will be

1. 2.45

2. 4.89

3. 5.98

4. 6.89

Subtopic:  pH calculation |
 73%
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