The electric field in a region is radially outward and at a point is given by E=250r V/m (where r is the distance of the point from origin). Calculate the charge contained in a sphere of radius 20 cm centred at the origin.

1. 2.22×10-6 C

2. 2.22×10-8 C

3. 2.22×10-10 C

4. Zero

Subtopic:  Gauss's Law |
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An isolated solid metal sphere of radius R is given an electric charge. Which of the graphs below best shows the way in which the electric field E varies with distance x from the centre of the sphere?

1. 

2. 

3. 

4. 

Subtopic:  Electric Field |
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The electric field intensity at P and Q in the shown arrangement are in the ratio of:

1. 1: 2

2. 2: 1

3. 1: 1

4. 4: 3

Subtopic:  Electric Field |
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Consider an atom with atomic number Z as consisting of a positive point charge at the centre and surrounded by a distribution of negative charges uniformly distributed within a sphere of radius R. The electric field at a point inside the atom at a distance r from the centre is:

1. Ze4πε001r2-rR3

2. Ze4πε01r2+1R3

3. 2Ze4πε0r2

4. Zero

Subtopic:  Gauss's Law |
 61%
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An electron is rotating around an infinite positive linear charge in a circle of radius 0.1 m. If the linear charge density is 1 μC/m, then the velocity of the electron in m/s will be:

1. 0.582×107

2. 5.62×107

3. 562×107

4. 0.0562×107

Subtopic:  Gauss's Law |
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For two infinitely long charged parallel sheets, the electric field at P will be:

1. σ2x-σ2(r-x)

2. σ2ε0x+σ2π(r-x)ε0

3. σε0

4. Zero

Subtopic:  Gauss's Law |
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When a test charge is brought in from infinity along the perpendicular bisector of an electric dipole, the work done is:

1. Positive

2. Zero

3. Negative

4. None of these

Subtopic:  Equipotential Surfaces |
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Two small spheres each carrying a charge q are placed at distance r apart. If one of the spheres is taken around the other in a circular path, the work done will be equal to:

1. Force between them × r

2. Force between them2πr

3. Force between them × 2πr

4. Zero

Subtopic:  Equipotential Surfaces |
 82%
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Work done in moving a charge q coulomb on the surface of a given charged conductor of potential V is:

1. Vq joule

2. Vq joule

3. qV joule

4. Zero

Subtopic:  Equipotential Surfaces |
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The variation of electric field between the two charges q1 and q2 along the line joining the charges is plotted against distance from q1 (taking rightwards direction of field as positive) as shown, then the correct statement is:

1. q1 and qare positive and q1 < q2

2. q1 and q2 are positive and q1 > q

3. q1 is positive and q2 is negative 

4. q1 is positive and qis negative  and  q1 < |q2|

Subtopic:  Electric Field |
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