On heating lead (II) nitrate gives a brown gas “A” The gas “A” on cooling changes to colourless solid “B”. Solid “B” on heating with NO changes to a blue solid ‘C’.

Identify ‘A’, ‘B’ and ‘C and also write reactions involved and draw the structures of ‘B’ and ‘C’.

 

1. A=NO_2​, B=N₂​O₄​ and C=N_2​O₃​.

2. A=N₂​O₄​_​, B=NO₂ and C=N_2​O₃​.

3. A=N₂​O₄​_​, B=N_2​O₃ and C=NO₂ 

4. None of above

On heating compound (A) gives a gas (B) which is a constituent of air. This gas when treated with 3 moles of hydrogen (H₂) in the presence of a catalyst gives another gas (C) which is basic in nature. Gas C on further oxidation in moist condition gives a compound (D) which is a part of acid rain. Compounds (A) and (D) are :
 

1. A = N₂ ;      D = HNO₃

2. A = NH₄NO₂ ;      D = HNO₃

3. A = NH₄NO₂ ;     D = NH₃

4. A = NH₄NO₂ ;     D = HNO₂

The disproportionation reaction of ${\mathrm{H}}_3{\mathrm{PO}}_3$ is as follows:

${\mathrm{H}}_3{\mathrm{PO}}_3$ $\stackrel{∆}{\to }$ $\mathrm{X}$ $+$ $\mathrm{Y}$

 X and Y in the above reaction are:

1. H₃PO₂, HPO₂  

2. H₃PO₄, PH₃

3. H₂PO₆, PO₃

4. None of the above.

The catalyst that is used in the contact process is:

The chemical formula of oleum is - 

The correct order of bond dissociation energy of halogens ${\text{F}}_2, {\mathrm{Cl}}_2, {\mathrm{Br}}_2 \mathrm{and} {\mathrm{I}}_2$ is-

1. F₂ < Cl₂ < Br₂ < I₂

2. I₂ > Br₂ > F₂ > Cl₂

3. Cl₂ > Br₂ < F₂ > I₂

4. I₂ < F₂ < Br₂ < Cl₂

The correct increasing order of basic strength of hydrides:

1. BiH₃ \(\simeq \) SbH₃ < AsH₃ < PH₃ < NH₃ 
2.  BiH₃  > NH₃  > PH₃ > SbH₃ > AsH₃ 
3. SbH₃ < AsH₃ < PH₃ < NH₃ < BiH₃ 
4. AsH₃ > NH₃ > PH₃ > SbH₃ > BiH₃