A metallic sphere is given some charge. Electric energy is stored

1. Only inside the sphere

2. Only outside the sphere

3. Both inside and outside

4. Neither inside nor outside

Two equal charges q are placed at a distance of 2a and a third charge –2q is placed at the midpoint. The potential energy of the system is -

1. $\frac{q^2}{8\pi {\epsilon }_{0}a}$

2. $\frac{6q^2}{8\pi {\epsilon }_{0}a}$

3. $-\frac{7q^2}{8\pi {\epsilon }_{0}a}$

4. $\frac{9q^2}{8\pi {\epsilon }_{0}a}$

Equipotential surfaces associated with an electric field which is increasing in magnitude along the x-direction are 

1. Planes parallel to yz-plane

2. Planes parallel to xy-plane

3. Planes parallel to xz-plane

4. Coaxial cylinders of increasing radii around the x-axis

What is the effective capacitance between A and B in the following figure 

1. 1 μF
2. 2 μF
3. 1.5 μF
4. 2.5 μF

In the figure, three capacitors each of capacitance 6 pF are connected in series. The total capacitance of the combination will be 

1. 9 × 10^–12 F

2. 6 × 10^–12 F

3. 3 × 10^–12 F

4. 2 × 10^–12 F

The charge on 4 μF capacitor in the given circuit is .... in μC 

1. 12

2. 24

3. 36

4. 32

A piece of cloud is having area \(25\times 10^{6}~\text{m}^2\) and an electric potential of \(10^5\) volts. If the height of cloud is \(0.75~\text{km}\), then find the energy of the electric field between the earth and the cloud will be: 
1. \(250~\text{J}\)
2. \(759~\text{J}\)
3. \(1225~\text{J}\)
4. \(1475~\text{J}\)

A parallel plate air capacitor has a capacitance of 100 μF. The plates are at a distance d apart. If a slab of thickness $t(t\le d)$ and dielectric constant 5 is introduced between the parallel plates, then the capacitance will be 

(1) 50 μμF

(2) 100 μμF

(3) 200 μμF

(4) 500 μμF

Five identical plates each of area A are joined as shown in the figure. The distance between the plates is d. The plates are connected to a potential difference of V volts. The charge on plates 1 and 4 will be 

(1) $\frac{{\epsilon }_{0}AV}{d}.\frac{2{\epsilon }_{0}AV}{d}$

(2) $\frac{{\epsilon }_{0}AV}{d}.\frac{2{\epsilon }_{0}AV}{d}$

(3) $\frac{{\epsilon }_{0}AV}{d}.\frac{-2{\epsilon }_{0}AV}{d}$

(4) $\frac{-{\epsilon }_{0}AV}{d}.\frac{-2{\epsilon }_{0}AV}{d}$

A network of four capacitors of capacity equal to $C_1=C,C_2=2C,C_3=3C$ and C₄ = 4 C are connected in a battery as shown in the figure. The ratio of the charges on C₂ and C₄ is 

(1) $\frac{22}{3}$

(2) $\frac{3}{22}$

(3) $\frac{7}{4}$

(4) $\frac{4}{7}$