The complex that will exhibit maximum ionic conductivity in aqueous solution is:
1. K4[Fe(CN)6]
2. [Co(NH3)6]Cl3
3. [Cu(NH3)4]Cl2
4. [Ni(CO)4]
solution mixed with solution in 1:1 molar ratio gives the test of Fe2+ ion but solution mixed with aqueous ammonia in 1:4 molar ratio does not give the test of Cu2+ ion because:
1. | The former is an example of a basic compound, while the latter is an amphoteric compound |
2. | The former is an example of an amphoteric compound, while the latter is a basic compound |
3. | The former is an example of a double salt, while the latter is a coordination compound |
4. | The former is an example of a coordination compound, while the latter is a double salt |
The oxidation number and coordination number of Co in respectively are:
1. 3, 6
2. 3, 2
3. 2, 2
4. 1, 3
Total number of optical isomers [Pt(NH3)(Br)(Cl)(py)] can show:
1. 3
2. 2
3. 1
4. 0
The difference between a weak field ligand and a strong field ligand is:
1. | Weak field ligands cause higher splitting in the d orbitals than strong field ligands. |
2. | Weak field ligands cause lower splitting in the d orbitals than strong field ligands. |
3. | Strong field ligands do not form a complex with a metal ion. |
4. | None of the above. |
The crystal field splitting energy is:
1. | The heat of formation between the two levels (e and t2) in tetrahedral splitting |
2. | The total pairing energy of the two levels (e and t2) in tetrahedral splitting. |
3. | The sum of the energy levels in an octahedral crystal field splitting. |
4. | The combined energy of the two levels (eg and t2g) in octahedral splitting. |
[Cr(NH3)6]3+ is paramagnetic ,while is diamagnetic because:
1. | Electrons in the 3d orbitals remain unpaired in |
2. | Electrons in the 3d orbitals remain unpaired in [Cr(NH3)6]3+ |
3. | Electrons in the 3p orbitals remain unpaired in [Cr(NH3)6]3+ |
4. | Electrons in the 3p orbitals remain unpaired in |
A solution of [Ni(H2O)6]2+ is green, but a solution of [Ni(CN)4]2– is colorless because:
1. | There are paired electrons in [Ni(H2O)6]2+ while all electrons are unpaired in [Ni(CN)4]2– |
2. | There are unpaired electrons in [Ni(H2O)6]2+ while all electrons are paired in [Ni(CN)4]2– |
3. | There are unpaired electrons in [Ni(H2O)6]2+ and [Ni(CN)4]2– |
4. | None of the above. |
[Fe(CN)6]4– and [Fe(H2O)6]2+ are of different colors in dilute solutions because :
1. | Higher lattice energy value of [Fe(CN)6]4– as compared to [Fe(H2O)6]2+ |
2. | Higher CFSE value of [Fe(CN)6]4– as compared to [Fe(H2O)6]2+ |
3. | Lower CFSE value of [Fe(CN)6]4– as compared to [Fe(H2O)6]2+ |
4. | Lower lattice energy value of [Fe(CN)6]4– as compared to [Fe(H2O)6]2+ |
The nature of bonding in metal carbonyls is -
1. | The metal-carbon bonds in metal carbonyls have both σ and π characters. |
2. | The metal-carbon bonds in metal carbonyls have only σ character. |
3. | The metal-carbon bonds in metal carbonyls have only π character. |
4. | The metal-carbon bonds in metal carbonyls have only hydrogen bonding. |