$$

The correct hybridization  of carbon atoms are:    

1. C₁= sp , C₂= sp³ , C₂= sp²

2. C₁= sp² , C₂= sp³ , C₂= sp³

3. C₁= sp³ , C₂= sp² , C₂= sp³

4. C₁= sp³ , C₂= sp³ , C₂= sp³

The correct hybridization states of carbon atoms in the following compound are - $\stackrel{1}{\mathrm{ \; \; C}}{H}_2=\stackrel{2}{C}H-\stackrel{3}{C}\equiv N$
 

The correct hybridization states of carbon atoms in C₆H_{6 (cyclic compound)} is/are:

1.  sp² 

2. sp

3. sp³

4.  All of the above

Structure 1.
Structure 2.

The Correct IUPAC names of the above structures are:

1. 2, 3–Dimethylbutanal & Heptan–4–one

2. 2, 4–Dimethylbutanal & Heptan–2–one

3. 2, 3–Dimethylbutanal & Heptan–3–one

4. 1, 2 –Dimethylbutanal & Heptan–4–one

The IUPAC name of the following compound is -

1.  4,4-Dimethyl-3-hydroxybutanoic acid
2. 2-Methyl-3-hydroxypentan-5-oic acid
3. 4-Methyl-3-hydroxypentanoic acid
4. 3-Hydroxy-4-methylpentanoic acid

The compound which shows metamerism is: 

What is the correct structure of 2,6-Dimethyl-dec-4-ene?

1.		2.
3.		4.

1. Only statement 'a' is true.

2. Only statement 'b' is true

3. Both statements are true

4. Both statements are false

The correct hybridization states of carbon atoms marked as 1,2,3 in the following compound are:
\({ }^1 \mathrm{CH}_3-\mathrm{ }^2{C} \mathrm{H}={}^3{\mathrm{C}} \mathrm{H}_2 \)

$\stackrel{1}{C}{H}_2$ $=\stackrel{2}{C}=O$

The correct hybridization states of carbon atoms in the above compound are -