The proposed mechanism for hydration of ethene to yield ethanol is as follows:

The wrong step in the above mechanism is:

1.	Step 1	2.	Step 2
3.	Step 3	4.	Both steps 2 and 3

The reaction of 3-methylbutan-2-ol with HBr gives:

The reaction of HI with methoxymethane will give-

1. Both methyl iodide and methanol

2. Only methanol

3. Only methyl iodide

4.  None of the above

The reaction of hydrogen iodide with 1-propoxypropane gives

1. Propane-1-ol and 1-Iodopropane

2. 1-iodopropane

3. Propane-1-ol

4. None of above

The correct sequence of reactions is:

1.
2.
3.
4.

The correct set of reactions among the following is:

1.
2.
3.
4.	None of the above

 
The major product of above Williamson's ether synthesis will be:
1. 1-Propoxypropane
2. 2-Propoxypropane
3. 3-Propoxypropane
4. 4-Propoxypropane

The incorrect reaction among the following is:

1.
2.
3.
4.

The major product of Williamson’s ether synthesis reaction would be:
 

In Williamson’s synthesis reaction major product will be

$$\begin{gathered} C{H}_{3 } \\ | \\ C{H}_3—C—ONa +C{H}_{3}Br\to ? \\ | \\ C{H}_3 \end{gathered}$$

1. 1-methoxy- 2-methylpropane

2. 2-methoxy- 2-methylpropane

3. 2-methoxy- 1-methylpropane

4. 1-methoxy- 1-methylpropane