In Kolbe’s reaction, 

 

the product formed will be:

1.  para-Salicylaldehyde

2.  ortho-Salicylaldehyde

3. para-Salicylic acid

4. ortho-Salicylic acid

In Reimer-Tiemann reaction, 

the product will be:

1. ortho-Salicylaldehyde

2. para-Salicylaldehyde

3. meta-Salicylaldehyde

4. All of the above

In the following Williamson ether synthesis reaction, what will be the major product?

1. 1-Methoxypropane

2. 2-Methoxypropane

3. 3-Methoxypropane

4. All of the above

Unsymmetrical ether will be the product in:

1. Kolbe’s reaction.

2. Reimer-Tiemann reaction.

3. Williamson ether synthesis.

4. None of the above.

The IUPAC name of the product that formed in the following chemical reaction is:
\(\text{Acetone}\xrightarrow[\bf\text{(ii) H}_2\text{O, H}^+]{\bf\text{(i) C}_2\text H_5\text{MgBr, dry Ether}}\text{Product } \)

Match the following:

	List I		List II
i.	O2N-C6H5-OCH3 (p)	a.	4-Ethoxy-1,1-dimethylcyclohexane
ii.	C2H5OCH2-CH(CH3)2	b.	1-Chloro-2-methoxyethane
iii.	CH3OCH2CH2Cl	c.	1-Ethoxy-2-methylpropane
iv.		d.	1-Methoxy-4-nitrobenzene

Dehydration of ethanol in acidic medium yields:

1. Ethyne

2. Ethanol

3. Ethane

4. Ethene

In the following Williamson’s synthesis reaction,

CH₃CH₂ONa + CH₃-Br → ?

The product will be:

In Williamson’s synthesis reaction major product will be

$$\begin{gathered} C{H}_{3 } \\ | \\ C{H}_3—C—ONa +C{H}_{3}Br\to ? \\ | \\ C{H}_3 \end{gathered}$$

1. 1-methoxy- 2-methylpropane

2. 2-methoxy- 2-methylpropane

3. 2-methoxy- 1-methylpropane

4. 1-methoxy- 1-methylpropane

The major product of Williamson’s ether synthesis reaction would be: