To minimize the painful effects accompanying deep sea diving, oxygen diluted with less soluble helium gas is used as breathing gas by the divers. This is an example of the application of:

1. Raoult's law 2. Henry's law
3. Ideal gas Equation 4. All of the above

Subtopic:  Concentration Terms & Henry's Law |
 83%
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The correct match for the below table is:
Type of solution  Example
a. Solid in gas i. Aerated water
b. Gas in liquid  ii. Smoke
c. Liquid in solid iii. Solution of hydrogen in palladium 
d. Gas in solid iv. Amalgams
   
a b c d
1. i iii iv ii
2. ii i iv iii
3. iii i iv ii
4. iv i ii iii
Subtopic:  Introduction & Colligative properties |
 77%
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The example of gas in a solid type solution is:

1. Solution of hydrogen in palladium.

2. Ethanol dissolved in water.

3. Camphor vapours in N2 gas.

4. Amalgams.

Subtopic:  Introduction & Colligative properties |
 80%
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The incorrect formula among the following is:
1. \(\text X_{\text{mole fraction}}=\frac{\text n_{\text{solute}}}{\text n_{\text{solution}}}\)
2. \(\text{Molarity}=\frac{\text{amount of solute (g)}}{\text{volume of solution (mL)}}\)
3. \(\text{Molality}=\frac{\text{Number of mole of solute}}{\text{amount of solvent (kg)}}\)
4. \(\text{Mass percentage}=\frac{\text{mass of the component in the solution}}{\text{Total mass of the solution}}\times100 \)
Subtopic:  Concentration Terms & Henry's Law |
 83%
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The density of 68 % nitric acid by mass in an aqueous solution is 1.504 g mL1. The molarity of the acid solution would be:
1. 15.24 M
2. 16.23 M
3. 14.52 M
4. 13.45 M

Subtopic:  Concentration Terms & Henry's Law |
 68%
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A solution of glucose (M.W = 180 g mol–1) in water is 10 % w/w. The mole fraction of each component in the solution is:

1. Mole fraction of glucose - 0.44; mole fraction of water - 0.56
2. Mole fraction of glucose - 0.056; mole fraction of water - 0.944
3. Mole fraction of glucose - 0.011; mole fraction of water - 0.99
4. Mole fraction of glucose - 0.36; mole fraction of water - 0.64
Subtopic:  Concentration Terms & Henry's Law |
 72%
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An antifreeze solution is prepared from 222.6 g of ethylene glycol (C2H6O2) and 200 g of water. The molality of the solution would be:

1. 6.9 m 2. 17.9 m
3. 29.9 m 4. 21.9 m
Subtopic:  Concentration Terms & Henry's Law |
 82%
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A drinking water sample was found to be contaminated with chloroform at a level of 15 ppm (by mass). What is the mass percent of chloroform in the sample?

1. 15×10-4

2. 1.5×10-4

3. 0.15×10-4

4. 15×10-5

Subtopic:  Concentration Terms & Henry's Law |
 64%
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The type of molecular interactions in a solution of alcohol and water is:

1. Electrostatic interaction 2. London dispersion forces
3. Hydrogen bonding 4. Ion-dipole interaction
Subtopic:  Raoult's Law |
 86%
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The graph representing Henry's law is given below:

    

The value of the slope will be

1. \(4\times10^{-4}~\mathrm{torr}\) 2. \(5\times10^{-4}~\mathrm{torr}\)
3. \(4\times10^{4}~\mathrm{torr}\) 4. \(5\times10^{4}~\mathrm{torr}\)

Subtopic:  Concentration Terms & Henry's Law |
 81%
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