A particle is thrown upwards from the ground. It experiences a constant resistance force which can produce retardation of \(2~\text{m/s}^2\). The ratio of the time of ascent to the time of descent is: \([g = 10~\text{m/s}^2]\)
1. \(1:1\)
2. \(\sqrt{\frac{2}{3}}\)
3. \(\frac{2}{3}\)
4. \(\sqrt{\frac{3}{2}}\)

Subtopic:  Uniformly Accelerated Motion |
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A bullet loses 120 of its velocity passing through a plank. The least number of planks required to stop the bullet is (All planks offers same retardation)

(1) 10

(2) 11

(3) 12

(4) 23

Subtopic:  Uniformly Accelerated Motion |
 59%
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A body starts from the origin and moves along the X-axis such that the velocity at any instant is given by (4t32t), where t is in sec and velocity in m/s. What is the acceleration of the particle, when it is 2 m from the origin ?

1. 28 m/s2

2. 22 m/s2

3. 12 m/s2

4. 10 m/s2

Subtopic:  Non Uniform Acceleration |
 63%
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The relation between time and distance is given by \(t=\alpha x^2+\beta x,\) where \(\alpha\) and \(\beta\) are constants. The retardation, as calculated based on this equation, will be (assume \(v\) to be velocity):
1. \(2\alpha v^3\)
2. \(2\beta v^3\)
3. \(2\alpha\beta v^3\)
4. \(2\beta^2 v^3\)

Subtopic:  Instantaneous Speed & Instantaneous Velocity |
 53%
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A point moves with uniform acceleration and v1, v2 and v3 denote the average velocities in the three successive intervals of time t1, t2 and t3. Which of the following relations is correct ?

(1) (v1v2):(v2v3)=(t1t2):(t2+t3)

(2) (v1v2):(v2v3)=(t1+t2):(t2+t3)

(3) (v1v2):(v2v3)=(t1t2):(t1t3)

(4) (v1v2):(v2v3)=(t1t2):(t2t3) 

Subtopic:  Uniformly Accelerated Motion |
 51%
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The acceleration of a moving body can be found from: 

(1) Area under the velocity-time graph

(2) Area under the distance-time graph

(3) Slope of the velocity-time graph

(4) Slope of the distance-time graph

Subtopic:  Graphs |
 75%
From NCERT
PMT - 1981
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The initial velocity of a particle is u (at t = 0) and the acceleration f is given by at. Which of the following relation is valid 

1. v=u+at2

2. v=u+at22

3. v=u+at

4. v = u

Subtopic:  Non Uniform Acceleration |
From NCERT
PMT - 1981
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The initial velocity of the particle is 10 m/sec and its retardation is 2 m/sec2. The distance moved by the particle in 5th second of its motion is 

(1) 1 m

(2) 19 m

(3) 50 m

(4) 75 m

Subtopic:  Uniformly Accelerated Motion |
 59%
PMT - 1976
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A motor car moving with a uniform speed of 20 m/sec comes to stop on the application of brakes after travelling a distance of 10 m. Its acceleration is 

(1) 20 m/sec2

(2) –20 m/sec2

(3) –40 m/sec2

(4) +2 m/sec2

Subtopic:  Uniformly Accelerated Motion |
 76%
From NCERT
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The velocity of a body moving with a uniform acceleration of 2 m/sec2 is 10 m/sec. Its velocity after an interval of 4 sec is 

(1) 12 m/sec

(2) 14 m/sec

(3) 16 m/sec

(4) 18 m/sec

Subtopic:  Uniformly Accelerated Motion |
 84%
From NCERT
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