Two simple pendulums have time periods T and 5T4. They start vibrating at the same instant from the mean position in the same phase. The phase difference between them when bigger pendulum completes one oscillation will be:

1. π6

2. π4

3. π3

4. π2

Subtopic:  Simple Harmonic Motion |
 61%
From NCERT
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A simple pendulum is oscillating without damping. When the displacement of the bob is less than maximum, its acceleration vector \(\vec a\) is correctly shown in: 

1. 2.
3. 4.
Subtopic:  Angular SHM |
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A second's pendulum is mounted in a rocket. Its period of oscillation decreases when the rocket:

(1) Comes down with uniform acceleration

(2) Moves around the earth in a geostationary orbit

(3) Moves up with a uniform velocity

(4) Moves up with the uniform acceleration

Subtopic:  Simple Harmonic Motion |
 60%
From NCERT
PMT - 1994
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There is a simple pendulum hanging from the ceiling of a lift. When the lift is stand still, the time period of the pendulum is T. If the resultant acceleration becomes g/4, then the new time period of the pendulum is 

(1) 0.8 T

(2) 0.25 T

(3) 2 T

(4) 4 T

Subtopic:  Angular SHM |
 82%
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A block \(P\) of mass \(m\) is placed on a frictionless horizontal surface. Another block \(Q\) of same mass is kept on \(P\) and connected to the wall with the help of a spring of spring constant \(k\) as shown in the figure. \(\mu_s\) is the coefficient of friction between \(P\) and \(Q\). The blocks move together performing SHM of amplitude \(A\). The maximum value of the friction force between \(P\) and \(Q\) will be:

         
1. \(kA\)
2. \(\frac{kA}{2}\)
3. zero
4. \(\mu_s mg\)

Subtopic:  Spring mass system |
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A small sphere carrying a charge ‘q’ is hanging in between two parallel plates by a string of length L. Time period of pendulum is T0. When parallel plates are charged, the electric field between the plates is E and time period changes to T. The ratio T/T0 is equal to 

(1) g+qEmg1/2           (2) gg+qEm3/2

(3) gg+qEm1/2           (4) None of these 

Subtopic:  Simple Harmonic Motion |
 64%
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If the displacement \(x\) and the velocity \(v\) of a particle executing simple harmonic motion are related through the expression \(4v^2= 25-x^2,\) then its time period will be:
1. \(\pi \) 2. \(2 \pi \)
3. \(4 \pi \) 4. \(6 \pi\)
Subtopic:  Linear SHM |
 66%
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The uniform stick of mass m length L is pivoted at the centre. In the equilibrium position shown in the figure, the identical light springs have their natural length. If the stick is turned through a small angle θ, it executes SHM. The frequency of the motion is:

(1) 12π6Km

(2) 12π3K2m

(3) 12π3Km

(4) None of these

Subtopic:  Angular SHM |
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A particle undergoes SHM with a time period of 2 seconds. In how much time will it travel from its mean position to a displacement equal to half of its amplitude?

(1) 12s

(2) 16s

(3) 14s

(4) 13s

Subtopic:  Simple Harmonic Motion |
 76%
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If a particle is executing SHM, with an amplitude \(A\), the distance moved and the displacement of the body in a time equal to its time period are, respectively:
1. \(2A,A\) 2. \(4A,0\)
3. \(A,A\) 4. \(0,2A\)
Subtopic:  Linear SHM |
 83%
From NCERT
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