The position of a particle moving in the XY plane at any time t is given by x=(3t26t) metres. Select the correct statement about the moving particle from the following.

1. The acceleration of the particle is zero at t = 0 second
2. The velocity of the particle is zero at t = 0 second
3. The velocity of the particle is zero at t = 1 second
4. The velocity and acceleration of the particle are never zero

Subtopic:  Instantaneous Speed & Instantaneous Velocity |
 72%
From NCERT
PMT - 1995
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If body having initial velocity zero is moving with uniform acceleration 8 m/sec2 , then the distance travelled by it in fifth second will be  

(1) 36 metres

(2) 40 metres

(3) 100 metres

(4) Zero

Subtopic:  Acceleration |
 84%
PMT - 1996
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An alpha particle enters a hollow tube of 4 m length with an initial speed of 1 km/s. It is accelerated in the tube and comes out of it with a speed of 9 km/s. The time for which it remains inside the tube is

(1) 8×103 s

(2) 80×103s

(3) 800×103s

(4) 8×104s

Subtopic:  Uniformly Accelerated Motion |
 59%
From NCERT
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Two cars A and B are travelling in the same direction with velocities v1 and v2 (v1>v2). When the car A is at a distance d behind car B, the driver of the car A applied the brake producing uniform retardation a. There will be no collision when-

1. d<(v1v2)22a

2. d<v12v222a

3. d>(v1v2)22a

4. d>v12v222a 

Subtopic:  Relative Motion in One Dimension |
 55%
From NCERT
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A body of mass 10 kg is moving with a constant velocity of 10 m/s. When a constant force acts for 4 seconds on it, it moves with a velocity 2 m/sec in the opposite direction. The acceleration produced in it is 

(1) 3 m/sec2

(2) –3 m/sec2

(3) 0.3 m/sec2

(4) –0.3 m/sec2

Subtopic:  Acceleration |
 77%
From NCERT
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A body starts from rest from the origin with an acceleration of \(6~\text{m/s}^2\) along the \(x\text-\)axis and \(8~\text{m/s}^2\) along the \(y\text-\)axis. Its distance from the origin after \(4\) seconds will be:
1. \(56~\text{m}\)
2. \(64~\text{m}\)
3. \(80~\text{m}\)
4. \(128~\text{m}\)

Subtopic:  Uniformly Accelerated Motion |
 75%
From NCERT
PMT - 1999
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A car moving with a velocity of 10 m/s can be stopped by the application of a constant force F in a distance of 20 m. If the velocity of the car is 30 m/s, it can be stopped by this force in 

(1) 203m

(2) 20 m

(3) 60 m

(4) 180 m

Subtopic:  Uniformly Accelerated Motion |
 73%
From NCERT
PMT - 1999
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The displacement of a particle is given by \(y = a + bt + ct^{2} - dt^{4}\). The initial velocity and acceleration are, respectively:

1. \(b, -4d\) 2. \(-b,2c\)
3. \(b, ~2c\) 4. \(2c, -2d\)
Subtopic:  Non Uniform Acceleration |
 82%
From NCERT
PMT - 1999
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A car moving with a speed of 40 km/h can be stopped by applying brakes for atleast 2 m. If the same car is moving with a speed of 80 km/h, what is the minimum stopping distance ?

(1) 8 m

(2) 2 m

(3) 4 m

(4) 6 m

Subtopic:  Uniformly Accelerated Motion |
 76%
From NCERT
PMT - 1998
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An elevator car, whose floor to ceiling distance is equal to \(2.7~\text{m}\), starts ascending with constant acceleration of \(1.2~\text{ms}^{-2}\). \(2\) sec after the start, a bolt begins falling from the ceiling of the car. The free fall time of the bolt is: 
1. \(\sqrt{0.54}~\text{s}\)
2. \(\sqrt{6}~\text{s}\)
3. \(0.7~\text{s}\)
4. \(1~\text{s}\)

Subtopic:  Relative Motion in One Dimension |
From NCERT
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