Q. No.The position \(x\) of a particle varies with time \(t\) as \(x=at^2-bt^3\). The acceleration of the particle will be zero at time \(t\) equal to:
1.
\(\dfrac{a}{b}\)
2.
\(\dfrac{2a}{3b}\)
3.
\(\dfrac{a}{3b}\)
4.
zero
If a train travelling at 72 kmph is to be brought to rest in a distance of 200 metres, then its retardation should be
1. 20 ms–2
2. 10 ms–2
3. 2 ms–2
4.1 ms–2
The displacement of a particle starting from rest (at t = 0) is given by . The time in seconds at which the particle will attain zero velocity again, is
1. 2
2. 4
3. 6
4. 8
Two cars A and B are at rest at the same point initially. If A starts with uniform velocity of 40 m/sec and B starts in the same direction with a constant acceleration of 4 m/s2, then B will catch A after how much time?
1. 10 sec
2. 20 sec
3. 30 sec
4. 35 sec
The motion of a particle is described by the equation where a = 15 cm and b = 3 cm/s2. Its instantaneous velocity at time 3 sec will be
1. 36 cm/sec
2. 18 cm/sec
3. 16 cm/sec
4. 32 cm/sec
A body travels for 15 sec starting from rest with constant acceleration. If it travels distances S1, S2 and S3 in the first five seconds, second five seconds and next five seconds respectively the relation between S1, S2 and S3 is
1.
2.
3.
4.
A body is moving according to the equation where x = displacement and a, b and c are constants. The acceleration of the body is
1.
2.
3.
4.
A particle travels 10 m in first 5 sec and 10m in the next 3 sec. Assuming constant acceleration what is the distance travelled in next 2 sec ?
1. 8.3 m
2. 9.3 m
3. 10.3 m
4. None of above
The distance travelled by a particle is proportional to the squares of time, then the particle travels with
1. Uniform acceleration
2. Uniform velocity
3. Increasing acceleration
4. Decreasing velocity
Velocity of a particle changes when
1. Direction of velocity changes
2. Magnitude of velocity changes
3. Both of above
4. None of the above
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