A car starts from rest and moves with uniform acceleration 'a' on a straight road from time t = 0 to t = T. After that, a constant deceleration brings it to rest. In this process the average speed of the car is:
1.
2.
3.
4. aT
An object accelerates from rest to a velocity of 27.5 m/s in 10 sec . Then find the distance covered by the object in the next 10 sec:
1. 550 m
2. 137.5 m
3. 412.5 m
4. 275 m
If the velocity of a particle is given by \(v = (180-16x)^{1/2}~\text{m/s}\), then its acceleration will be:
1. | zero | 2. | \(8\) m/s2 |
3. | \(-8\) m/s2 | 4. | \(4\) m/s2 |
The displacement of a particle is proportional to the cube of time elapsed. How does the acceleration of the particle depends on time obtained
1.
2.
3.
4.
Starting from rest, acceleration of a particle is The velocity of the particle at is:
1. 15 m/sec
2. 25 m/sec
3. 5 m/sec
4. None of these
Speed of two identical cars are u and 4u at a specific instant. The ratio of the respective distances in which the two cars are stopped from that instant is:
1. 1 : 1
2. 1 : 4
3. 1 : 8
4. 1 : 16
A body is moving with uniform acceleration describes 40 m in the first 5 sec and 65 m in the next 5 sec. Its initial velocity will be:
1. 4 m/s
2. 2.5 m/s
3. 5.5 m/s
4. 11 m/s
The displacement x of a particle varies with time , where are positive constants. The velocity of the particle will
1. Go on decreasing with time
2. Be independent of and
3. Drop to zero when =
4. Go on increasing with time
A car, starting from rest, accelerates at the rate f through a distance S, then continues at a constant speed for time t and then decelerates at the rate to come to rest. If the total distance traversed is 15 S, then,
1.
2.
3.
4.
A man is 45 m behind the bus when the bus starts accelerating from rest with acceleration of 2.5 m/s2. With what minimum velocity should the man start running to catch the bus?
1. 12 m/s
2. 14 m/s
3. 15 m/s
4. 16 m/s