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Q. No.In the following questions a statement of assertion (A) is followed by a statement of reason (R).
Assertion (A):
Organisms lacking one complete chromosome are called monosomics.
Reason (R):
Down’s syndrome is an example of monosomy.
1.
Both (A) and (R) are true and (R) is the correct explanation of (A).
2.
Both (A) and (R) are true but (R) is not the correct explanation of (A).
3.
(A) is true but (R) is false.
4.
Both (A) and (R) are false.
- If both the assertion and the reason are true and the reason is a correct explanation of the assertion
- If both the assertion and reason are true but the reason is not a correct explanation of the assertion
- If the assertion is true but the reason is false
- If both the assertion and reason are false
- If both the assertion and the reason are true and the reason is a correct explanation of the assertion
- If both the assertion and reason are true but the reason is not a correct explanation of the assertion
- If the assertion is true but the reason is false
- If both the assertion and reason are false
Subtopic: Non - Disjunction & Aneuploidy | Sex Aneuploidy - Turner & Klinefelter Syndrome |
70%
Level 2: 60%+
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Cystic fibrosis affects the lungs, the pancreas, the digestive system, and other organs, resulting in symptoms ranging from breathing difficulties to recurrent infections. Which of the following terms best describes this?
1. incomplete dominance
2. multiple alleles
3. pleiotropy
4. epistasis
1. incomplete dominance
2. multiple alleles
3. pleiotropy
4. epistasis
Subtopic: Polygenic Inheritance & Pleiotropy | Mendelian Disorders |
80%
Level 1: 80%+
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How would one explain a test cross involving F1 dihybrid flies in which more parental-type offspring than recombinant-type offspring are produced?
1. The two genes are closely linked on the same chromosome
2. The two genes are linked but on different chromosomes
3. Recombination did not occur in the cell during meiosis
4. The test cross was improperly performed
1. The two genes are closely linked on the same chromosome
2. The two genes are linked but on different chromosomes
3. Recombination did not occur in the cell during meiosis
4. The test cross was improperly performed
Subtopic: Understanding Linkage | Linkage Types | Recombination & Gene Mapping |
84%
Level 1: 80%+
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In a linear chromosome map distances between four loci are -a and b = 20 mu; a and d = 6mu; b and c=8 mu; a and c= 12 mu. What will be the crossover frequency between c and d ?
1. 12%
2. 20%
3. 3%
4. 6%
1. 12%
2. 20%
3. 3%
4. 6%
Subtopic: Chromosomal Basis of Inheritance: Introduction | Linkage Types | Recombination & Gene Mapping |
64%
Level 2: 60%+
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Which of the following display female heterogametry?
1. Drosophila melanogaster
2. Apis mellifera
3. Gallus gallus domesticus
4. Periplaneta Americana
1. Drosophila melanogaster
2. Apis mellifera
3. Gallus gallus domesticus
4. Periplaneta Americana
Subtopic: Sex Determination | Sex Determination: Further Considerations |
58%
Level 3: 35%-60%
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In a particular chromosome, the recombination frequency between genes a &c is 5%; b & c is 15%; b &d is 9%; a &b is 20%; c &d is 24% and a & d is 29%. The sequence of genes in a chromosome is
1. a, d, b, c
2. d, b, a, c
3. a, b, c, d
4. a, c, b, d
1. a, d, b, c
2. d, b, a, c
3. a, b, c, d
4. a, c, b, d
Subtopic: Chromosomal Basis of Inheritance: Introduction | Recombination & Gene Mapping |
73%
Level 2: 60%+
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Match List I with List II
Choose the correct answer from the options given below:
1. A-III B-I C-II D-IV
2. A-III B- IV C-II D-I
3. A-IV B-III C-II D-I
4. A-II B-III C-I D-IV
| List I | List II |
| A. Mendelian Disorder | I. Chromosomal Theory of inheritance |
| B. Alfred Sturtevant | II. Klinefelter's syndrome |
| C. Chromosomal Disorder | III. Cystic fibrosis |
| D. Sutton and Boveri | IV. Used the frequency of recombination between the gene pair in the same chromosome |
Choose the correct answer from the options given below:
1. A-III B-I C-II D-IV
2. A-III B- IV C-II D-I
3. A-IV B-III C-II D-I
4. A-II B-III C-I D-IV
Subtopic: Chromosomal Basis of Inheritance: Introduction | Chromosomal Basis of Inheritance: Further Considerations | Recombination & Gene Mapping | Mendelian Disorders |
66%
Level 2: 60%+
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If two plants having heterozygous genotype for a trait are crossed, what percentage of the progeny will have heterozygous genotype?
1. 25%
2. 50%
3. 75%
4. 100%
1. 25%
2. 50%
3. 75%
4. 100%
Subtopic: Monohybrid Cross: 1 | Monohybrid Cross: Further Understanding |
86%
Level 1: 80%+
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Phenylketonuria is a
1. Sex-linked dominant disease
2. Autosomal dominant disease
3. Sex-linked recessive disease
4. Autosomal recessive disease
1. Sex-linked dominant disease
2. Autosomal dominant disease
3. Sex-linked recessive disease
4. Autosomal recessive disease
Subtopic: Mendelian Disorders |
82%
Level 1: 80%+
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Which of the following are true of sex linked inhertiance in humans?
A. Males are considered to be hemizygous for genes present on X-chromosome
B. Majority of sex-linked traits are carried on the X-chromosome
C. Genes that are not sex-linked are present in somatic cells and absent in germ cells
D. 1:1 ratio of males and females in humans is a result of meiosis in males
E. The single X-chromosome present in the father is inherited by the son (male-to-male transmission)
Choose the correct answer from the options given below:
1. A and B only
2. B and D only
3. A, B and C only
4. B, D and E only
A. Males are considered to be hemizygous for genes present on X-chromosome
B. Majority of sex-linked traits are carried on the X-chromosome
C. Genes that are not sex-linked are present in somatic cells and absent in germ cells
D. 1:1 ratio of males and females in humans is a result of meiosis in males
E. The single X-chromosome present in the father is inherited by the son (male-to-male transmission)
Choose the correct answer from the options given below:
1. A and B only
2. B and D only
3. A, B and C only
4. B, D and E only
Subtopic: Sex Determination |
Level 3: 35%-60%
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