A particle moves with constant speed \(v\) along a circular path of radius \(r\) and completes the circle in time \(T\). The acceleration of the particle is:
1. \(2\pi v / T\)
2. \(2\pi r / T\)
3. \(2\pi r^2 / T\)
4. \(2\pi v^2 / T\)

Subtopic:  Circular Motion |
 62%
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In \(1.0~\text{s}\), a particle goes from point \(A\) to point \(B\), moving in a semicircle of radius \(1.0~\text{m}\) (see figure). The magnitude of the average velocity is:

          
1. \(3.14~\text{m/s}\)
2. \(2.0~\text{m/s}\)
3. \(1.0~\text{m/s}\)
4. zero

Subtopic:  Speed & Velocity |
 70%
From NCERT
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A stone tied to the end of a string of \(1\) m long is whirled in a horizontal circle with a constant speed. If the stone makes \(22\) revolutions in \(44\) s, what is the magnitude and direction of acceleration of the stone?

1. \(\dfrac{\pi^2}{4}\) ms–2 and direction along the radius towards the center
2. \(\pi^2\) ms–2 and direction along the radius away from the center
3. \(\pi^2 \) ms–2 and direction along the radius towards the center
4. \(\pi^2\) ms 2 and direction along the tangent to the circle
Subtopic:  Circular Motion |
 73%
From NCERT
PMT - 2005
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If the equation for the displacement of a particle moving on a circular path is given by \(\theta = 2t^3 + 0.5\) where \(\theta\) is in radians and \(t\) in seconds, then the angular velocity of the particle after \(2\) sec from its start is:
1. \(8\) rad/sec
2. \(12\) rad/sec
3. \(24\) rad/sec
4. \(36\) rad/sec

Subtopic:  Circular Motion |
 82%
From NCERT
AIIMS - 1998
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For a particle in a non-uniform accelerated circular motion 

(1) Velocity is radial and acceleration is transverse only

(2) Velocity is transverse and acceleration is radial only

(3) Velocity is radial and acceleration has both radial and transverse components

(4) Velocity is transverse and acceleration has both radial and transverse components

Subtopic:  Circular Motion |
 61%
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The coordinates of a moving particle at any time \(t\) are given by \(x= \alpha t^3\) and \(y = \beta t^3.\) The speed of the particle at a time \(t\) is given by:

1. \(\sqrt{\alpha^{2} + \beta^{2}}\) 2. \(3t \sqrt{\alpha^{2} + \beta^{2}}\)
3. \(3t^{2} \sqrt{\alpha^{2} +\beta^{2}}\) 4. \(t^{2} \sqrt{\alpha^{2} +\beta^{2}}\)
Subtopic:  Speed & Velocity |
 79%
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The figure shows a body of mass m moving with a uniform speed v along a circle of radius r. The change in velocity in going from A to B is:

(1) v2

(2) v/2

(3) v

(4) zero

Subtopic:  Circular Motion |
 65%
From NCERT
PMT - 2004
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A particle moves in a circular path with decreasing speed. Choose the correct statement. 

(1) Angular momentum remains constant

(2) Acceleration (a) is towards the center

(3) Particle moves in a spiral path with decreasing radius

(4) The direction of angular momentum remains constant

Subtopic:  Projectile Motion |
From NCERT
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The angle turned by a body undergoing circular motion depends on time as θ=θ0+θ1t+θ2t2. Then the angular acceleration of the body is 

(1) θ1

(2) θ2

(3) 2θ1

(4) 2θ2

Subtopic:  Circular Motion |
 85%
From NCERT
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A stone is just released from the window of a train moving along a horizontal straight track. The stone will hit the ground following

(1) Straight path

(2) Circular path

(3) Parabolic path

(4) Hyperbolic path

Subtopic:  Projectile Motion |
 83%
From NCERT
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