1. | Thalassemia | 2. | Sickle cell anemia |
3. | Haemophilia | 4. | Phenylketonuria |
1. | 9 | 2. | 16 |
3. | 4 | 4. | 6 |
A: | There is a change in the gene for beta-globin |
B: | In beta-globin, there is a valine in place of Lysine |
C: | It is an example of point mutation |
D: | In the normal gene, U is replaced by A |
1. | (B), (C) and (D) only | 2. | (B) and (D) only |
3. | (A), (B) and (D) only | 4. | (A) and (C) only |
A: | It is an example of female heterogamety |
B: | Male produces two different types of gametes either with or without X chromosomes. |
C: | Total number of chromosomes (autosomes and sex chromosomes) is same in both males and females. |
D: | All eggs bear an additional X chromosome besides the autosomes. |
1. | (B) and (D) only | 2. | (A), (C) and (D) only |
3. | (A) only | 4. | (A) and (C) only |
Assertion (A): | In Mendelian experiments, phenotype of F1 heterozygote is exactly like the dominant parent in appearance. |
Reason (R): | In a pair of dissimilar factors, one dominates the other while other factor is recessive. |
1. | Both (A) and (R) are true and (R) is the correct explanation of (A). |
2. | Both (A) and (R) are true but (R) is not the correct explanation of (A). |
3. | (A) is true but (R) is false. |
4. | Both (A) and (R) are false. |
Assertion (A): | The original phenotype is due to dominant allele and the recessive phenotype is due to modified allele. |
Reason (R): | The dominant allele produces functional enzyme and the modified alleles generally produce non-functional or no enzyme at all. |
1. | Both (A) and (R) are true and (R) is the correct explanation of (A). |
2. | Both (A) and (R) are true but (R) is not the correct explanation of (A). |
3. | (A) is true but (R) is false. |
4. | Both (A) and (R) are false. |
Assertion (A): | When \(I^A\) and \(I^B \) are present together, they both express their own types of sugars. |
Reason (R): | Alleles \(I^A\) and \(I^B \) show incomplete dominance. |
1. | Both (A) and (R) are true and (R) is the correct explanation of (A). |
2. | Both (A) and (R) are true but (R) is not the correct explanation of (A). |
3. | (A) is true but (R) is false. |
4. | Both (A) and (R) are false. |
Assertion (A): | A recessive character that is not expressed in heterozygous condition can express when it becomes homozygous. |
Reason (R): | Characters segregate during the formation of gametes. |
1. | Both (A) and (R) are true and (R) is the correct explanation of (A). |
2. | Both (A) and (R) are true but (R) is not the correct explanation of (A). |
3. | (A) is true but (R) is false. |
4. | Both (A) and (R) are false. |
Assertion (A): | Externally it is not possible to distinguish between the pea plants with the genotypes TT or Tt regarding their heights. |
Reason (R): | Due to the dominance of one trait over the other, 3/4th of the F2 plants in Mendelian monohybrid cross were tall. |
1. | Both (A) and (R) are true and (R) is the correct explanation of (A). |
2. | Both (A) and (R) are true but (R) is not the correct explanation of (A). |
3. | (A) is true but (R) is false. |
4. | Both (A) and (R) are false. |
Assertion (A): | In each pregnancy there is always 50 percent probability of either a male or a female child. |
Reason (R): | Genetic makeup of the sperm determines the sex of a child. |
1. | Both (A) and (R) are true and (R) is the correct explanation of (A). |
2. | Both (A) and (R) are true but (R) is not the correct explanation of (A). |
3. | (A) is true but (R) is false. |
4. | Both (A) and (R) are false. |