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Q. No.
Given below are two statements:
Assertion (A):
If both strands of DNA acts as a template, they would code for RNA molecule with different sequences.
Reason (R):
The sequence of amino acid coded by them in the proteins would be different.
1.
Both (A) and (R) are true and (R) is the correct explanation of (A).
2.
Both (A) and (R) are true but (R) is not the correct explanation of (A).
3.
(A) is true but (R) is false.
4.
Both (A) and (R) are false.
Subtopic: Transcription |
From NCERT
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Given below are two statements:
| Assertion (A): | If two RNA molecules are produced simultaneously, they would be complementary to each other and form a double stranded RNA. |
| Reason (R): | The double stranded RNA would never prevent it from being translated into protein. |
| 1. | Both (A) and (R) are true and (R) is the correct explanation of (A). |
| 2. | Both (A) and (R) are true but (R) is not the correct explanation of (A). |
| 3. | (A) is true but (R) is false. |
| 4. | Both (A) and (R) are false. |
Subtopic: Transcription |
61%
From NCERT
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Given below are two statements:
| Assertion (A): | Structural gene in lac operon is polycistronic. |
| Reason (R): | Structural gene in lac operon is responsible for lactose metabolism. |
| 1. | Both (A) and (R) are true and (R) is the correct explanation of (A). |
| 2. | Both (A) and (R) are true but (R) is not the correct explanation of (A). |
| 3. | (A) is true but (R) is false. |
| 4. | Both (A) and (R) are false. |
Subtopic: Gene Regulation: Lac Operon |
78%
From NCERT
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Given below are two statements:
| Assertion (A): | Primary transcripts in eukaryotes are non-functional. |
| Reason (R): | Primary transcripts in eukaryotes have interrupted exons. |
| 1. | Both (A) and (R) are true and (R) is the correct explanation of (A). |
| 2. | Both (A) and (R) are true but (R) is not the correct explanation of (A). |
| 3. | (A) is true but (R) is false. |
| 4. | Both (A) and (R) are false. |
Subtopic: Transcription |
58%
From NCERT
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Given below are two statements:
| Assertion (A): | UAA functions as stop codon. |
| Reason (R): | UAA does not code for any amino acid. |
| 1. | Both (A) and (R) are true and (R) is the correct explanation of (A). |
| 2. | Both (A) and (R) are true but (R) is not the correct explanation of (A). |
| 3. | (A) is true but (R) is false. |
| 4. | Both (A) and (R) are false. |
Subtopic: Genetic Code |
77%
From NCERT
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Given below are two statements:
| Assertion (A): | Genetic codons are called degenerate. |
| Reason (R): | Some amino acids are coded by more than one codon. |
| 1. | Both (A) and (R) are true and (R) is the correct explanation of (A). |
| 2. | Both (A) and (R) are true but (R) is not the correct explanation of (A). |
| 3. | (A) is true but (R) is false. |
| 4. | Both (A) and (R) are false. |
Subtopic: Genetic Code |
86%
From NCERT
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In the experiments conducted by Griffith on Streptococcus pneumoniae, it is observed that:
| 1. | Mice infected with non-pathogenic strain become resistant to pathogenic stain. |
| 2. | Heat-killed pathogenic strain is responsible for making non-pathogenic to pathogenic ones. |
| 3. | Non-pathogenic strain when mixed with pathogenic strain, the latter is also converted into non-pathogenic. |
| 4. | Mutant strain of bacterium makes the mice mutant also. |
Subtopic: Search for Genetic Material |
83%
From NCERT
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To determine DNA as genetic material, Hershey and Chase labelled
1. DNA with radioactive phosphorus
2. Protein with P32
3. DNA with radioactive sulphur
4. Protein with S32
1. DNA with radioactive phosphorus
2. Protein with P32
3. DNA with radioactive sulphur
4. Protein with S32
Subtopic: Search for Genetic Material |
83%
From NCERT
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How many nucleosomes are present in the nucleus of diploid eukaryotic cell which possess 6.6 x 109 bp?
1. 3.3 x 107
2. 6.6 x 106
3. 6.6 x 108
4. 3.3 x 109
1. 3.3 x 107
2. 6.6 x 106
3. 6.6 x 108
4. 3.3 x 109
Subtopic: DNA Packaging |
64%
From NCERT
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When the Escherichia coli growing in a medium containing 35SO4 are infected with T2 bacteriophage, which of the following results would be observed?
| 1. | Radioactivity will be observed in the supernatant. |
| 2. | The bacteriophage formed in the bacteria will not show radioactivity. |
| 3. | Radioactivity will be seen in the genetic material of the bacteria. |
| 4. | Radioactivity will be seen in the capside of the newly formed bacteriophage. |
Subtopic: Search for Genetic Material |
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