In Mendel's dihybrid cross, by taking the characters seed shape and seed colour in pea plant, the phenotypic ratio in F2 generation 9 : 3 : 3 : 1 is obtained. This is because 
 
1. Genes for both the characters are located on the same chromosomes and follow the law of dominance 
2. Alleles of seed shape and seed colour are present on the same locus of a pair of homologous chromosomes
3. Genes for both the characters are present on different chromosomes and follow law of dominance 
4. Genes for seed shape and seed colour are present on the different loci of the same chromosome and follow the law of codominance 

Subtopic:  Dihybrid Cross: General Consideration |
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Which of the given is not related to aneuploidy?
 
1. Arise due to failure of segregation of chromatids during cell cycle 
2. There is increase in whole set of chromosomes
3. Exemplified by Down's syndrome
4. Involves gain or loss of one or a few chromosomes 

 
Subtopic:  Non - Disjunction & Aneuploidy |
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The traits related to pea plants considered by Mendel in his experiments, how many were related to pod?
1. Four 
2. Six
3. Eight
4. Two
 
Subtopic:  Introduction to Genetics: 1 | Introduction to Genetics: 2 |
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A pleiotropic gene
1. Express many traits that spread across a gradient
2. Has more than two alleles
3. Controls different characters
4. Always follows Mendel's law of dominance
Subtopic:  Polygenic Inheritance & Pleiotropy |
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If a hybrid tall pea plant is selfed, what percent of F1 individuals would be of true breeding line regarding the plant height?
1. 50% 
2. 12.5%
3. 100% 
4. 25%
 
Subtopic:  Monohybrid Cross: 1 |
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The recombination frequency between genes A and B present on X chromosome is 17% while that of C and D is 13%.
Select the correct option concluded from above given information.
1. Genes A and B are closely situated than genes C and D
2. Genes A and B are completely inked.
3. Genes A and B must be present on one chromatid and C and D on its sister chromatid
4. Genes A and B are distantly situated than genes C and D 
Subtopic:  Recombination & Gene Mapping |
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A colourblind male marries to a normal female and they have their first child as colourblind female, What will be the genotype of the father and mother respectively?
1. XCY, XX
2. XCY, XCX
3. XY, XCXC
4. XY, XCX
Subtopic:  Mendelian Disorders |
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Only half of the individuals obtained in Filialprogeny of pea plants produce violet flowers. Which of the following cannot be the correct conclusion regarding this character about parents?
1. One of the parents is homozygous and other is heterozygous
2. One of the parents must had white flowers
3. Cross between these parents will never produce pure violet flowered progeny 
4. Both the parents are heterozygous 
Subtopic:  Monohybrid Cross: 1 |
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In a test cross AaBb × aabb, all the progenies were like parents only. it means
1. Genes are distantly situated
2. Genes A and B are completely linked
3. Crossing over occurred during gamete formation 
4. Genes A and B are incompletely linked
Subtopic:  Dihybrid Cross Analysis | Dihybrid Cross: Details |
 70%
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A haemophilic male
1. Can pass the disorder to daughters only
2. Produces all the sperms with gene of haemophilia 
3. Can be a carrier for the disorder 
4. Inherit the haemophilia gene from his father only 
Subtopic:  Mendelian Disorders: Hemophilia |
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