$\text{PhOH\hspace{0.17em}}\underset{\text{NaOH}}{\overset{{\text{Me}}_{\text{2}}{\text{SO}}_{\text{4}}}{\to }}\text{\hspace{0.17em}P,}$ P is

(1) Ph–O–SO₂OMe

(2) PhOMe

(3) PhOSO₂OPh

(4) PhMe

Which of the following statement is correct

(1)
(2)
(3)
(4)

Product is

(1) CH₃ – CH₂ – S – CH₂ – CH₂ – OH

(2) CH₃ – CH₂ – O – CH₂ – CH₂ – OH

(3)

(4)

Product, Product is

(1)
(2)
(3)
(4)

In the reaction The product is –

1.
2.
3.
4.

(1) R

(2) S

(3) R, S both

(4) None of these

A diol compound with the structure shown below is treated with acid (H⁺) to give product A.


Identify the correct structure of product A.

1.
2.
3.
4.	None of the above .

The products of hydrolysis of:

1. HOCH₂CH₂CH₂CH₂ CHO + CH₃CHO

2. HOCH₂CH₂CH₂CH₂OH + CH₃CHO

3. HOCH₂CH₂CH₂CH₂CHO + C₂H₅OH

4. HOCH₂CH₂CH₂CH₂CH₂OH + C₂H₅OH

The product A is :

(1)
(2)
(3)
(4)

(CH₃)₃CCI + (CH₃)₃C${\mathrm{O}}^{-}$ K⁺ → Product

1. S_N Product will be more

2. E₂ Product will be more

3. Both will be the same

4. None of the above