A block of mass m is placed on a smooth wedge of inclination θ. The whole system is accelerated horizontally so that the block does not slip on the wedge. The force exerted by the wedge on the block (g is acceleration due to gravity) will be 

1. $mg \cos \theta$

2. $mg \sin \theta$

3. mg

4. $mg/\cos \theta$

The linear momentum p of a body moving in one dimension varies with time according to the equation p = a + bt² where a and b are positive constants. The net force acting on the body is 

1. A constant

2. Proportional to t²

3. Inversely proportional to t

4. Proportional to t

A man of weight 80 kg is standing in an elevator which is moving with an acceleration of 6 m/s² in upward direction. The apparent weight of the man will be (g = 10 m/s²) 

1. 1480 N

2. 1280 N

3. 1380 N

4. None of these

N bullets each of mass m kg are fired with a velocity v ms^–1 at the rate of n bullets per second upon a wall. The reaction offered by the wall to the bullets is given by:

1. nmv

2. $\frac{Nmv}{n}$

3. $n\frac{Nm}{v}$

4. $n\frac{Nv}{m}$

With what minimum acceleration can a fireman slides down a rope while breaking strength of the rope is $\frac{2}{3}$ of his weight 

1. $\frac{2}{3}g$

2. g

3. $\frac{1}{3}g$

4. Zero

A ball of mass m moves with speed v and it strikes normally with a wall and reflected back normally, if its time of contact with wall is t then find force exerted by ball on wall 

1. $\frac{2mv}{t}$

2. $\frac{mv}{t}$

3. mvt

4. $\frac{mv}{2t}$

A body of mass 5 kg starts from the origin with an initial velocity $\overrightarrow{u}=30\hat{i}+40\hat{j}m{s}^{-1}$. If a constant force $\overrightarrow{F}=-(\hat{i}+5\hat{j})N$ acts on the body, the time in which the y–component of the velocity becomes zero is 

1. 5 seconds

2. 20 seconds

3. 40 seconds

4. 80 seconds

A ball of mass 0.5 kg moving with a velocity of 2 m/sec strikes a wall normally and bounces back with the same speed. If the time of contact between the ball and the wall is one millisecond, the average force exerted by the wall on the ball is:

1. 2000 N

2. 1000 N

3. 5000 N

4. 125 N

A particle moves in the \(XY\text-\)plane under the action of a force \(F\) such that the components of its linear momentum \(p\) at any time \(t\) are \(p_x = 2 \cos t\),  \(p_y = 2 \sin t\). The angle between \(F\) and \(p\) at time \(t\) will be: