In the circuit shown below, The reading of the voltmeter V is 

(1) 12 V

(2) 8 V

(3) 20 V

(4) 16 V

In the figure given the value of X resistance will be, when the p.d. between B and D is zero 

(1) 4 ohm

(2) 6 ohm

(3) 8 ohm

(4) 9 ohm

Five resistors of given values are connected together as shown in the figure. The current in the arm BD will be 

(1) Half the current in the arm ABC

(2) Zero

(3) Twice the current in the arm ABC

(4) Four times the current in the arm ABC

In the network shown in the figure, each of the resistance is equal to 2 Ω. The resistance between the points A and B is 

(1) 1 Ω

(2) 4 Ω

(3) 3 Ω

(4) 2 Ω

In the arrangement of resistances shown below, the effective resistance between points A and B is

(1) 20 Ω

(2) 30 Ω

(3) 90 Ω

(4) 110 Ω

In the given figure, when galvanometer shows no deflection, the current (in ampere) flowing through 5 Ω resistance will be 

(1) 0.5

(2) 0.6

(3) 0.9

(4) 1.5

In the Wheatstone's bridge shown, P = 2 Ω, Q = 3 Ω, R = 6 Ω and S = 8 Ω. In order to obtain balance, shunt resistance across 'S' must be [SCRA 1998]

(1) 2 Ω

(2) 3 Ω

(3) 6 Ω

(4) 8 Ω

Potential difference between the points P and Q in the electric circuit shown is 

(1) 4.5 V

(2) 1.2 V

(3) 2.4 V

(4) 2.88 V

In a typical Wheatstone network, the resistances in cyclic order are A = 10 Ω, B = 5 Ω, C = 4 Ω and D = 4 Ω for the bridge to be balanced 

(1) 10 Ω should be connected in parallel with A

(2) 10 Ω should be connected in series with A

(3) 5 Ω should be connected in series with C

(4) 5 Ω should be connected in parallel with B

In the circuit shown in figure, the current drawn from the battery is 4A. If 10 Ω resistor is replaced by 20 Ω resistor, then current drawn from the circuit will be 

(1) 1 A

(2) 2 A

(3) 3 A

(4) 4 A