A moving coil galvanometer has a resistance of 50 Ωand gives full scale deflection for 10 mA. How could it be converted into an ammeter with a full scale deflection for 1A :

1. 50/99 Ω in series

2. 50/99 Ω in parallel

3. 0.01 Ω in series

4. 0.01 Ω in parallel

The resistance of an ideal voltmeter is 

1. Zero

2. Very low

3. Very large

4. Infinite

The net resistance of a voltmeter should be large to ensure that :

A galvanometer having a resistance of $8~\Omega$ is shunted by a wire of resistance $2~\Omega$. If the total current is $1~\text{A}$, the part of it passing through the shunt will be:
1. $0.25~\text{A}$
2. $0.8~\text{A}$
3. $0.2~\text{A}$
4. $0.5~\text{A}$

A voltmeter of resistance 1000 Ω gives full-scale deflection when a current of 100 mA flow through it. The shunt resistance required across it to enable it to be used as an ammeter reading 1 A at full-scale deflection is :

1. 10000 Ω

2. 9000 Ω

3. 222 Ω

4. 111 Ω

If an ammeter $A$ reads $2$ A and the voltmeter $V$ reads $20$ V, what is the value of resistance $R$? (Assuming finite resistances of ammeter and voltmeter)
            

A galvanometer has a resistance of 25 ohm and a maximum of 0.01 A current can be passed through it. In order to change it into an ammeter of range 10 A, the shunt resistance required is 

1. 5/999 ohm

2. 10/999 ohm

3. 20/999 ohm

4. 25/999 ohm

A galvanometer has 30 divisions and a sensitivity 16$\mu A/\text{div.}$ It can be converted into a voltmeter to read 3 V by connecting (approximately):

1. Resistance nearly 6 k Ω in series

2. 6 k Ω in parallel

3. 500 Ω in series

4. It cannot be converted

A voltmeter has a range 0-V with a series resistance R. With a series resistance 2R, the range is 0-V'. The correct relation between V and V' is :

1. $V^{\text{'}}=2V$

2. $V^{\text{'}}>2V$

3. $V^{\text{'}}>>2V$

4. $V\text{'}<2V$