The potential difference across the 100Ω resistance in the following circuit is measured by a voltmeter of 900 Ω resistance. The percentage error made in reading the potential difference is :

(1) 109

(2) 0.1

(3) 1.0

(4) 10.0

Subtopic:  EMF & Terminal Voltage |
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A galvanometer with a resistance of \(36~\Omega\) is changed into an ammeter by using a shunt of \(4~\Omega\). The fraction \(f_0\) of total current passing through the galvanometer will be:
1. \(\dfrac{1}{40}\) 2. \(\dfrac{1}{4}\)
3. \(\dfrac{1}{140}\) 4. \(\dfrac{1}{10}\)
Subtopic:  Conversion to Ammeter & Voltmeter |
 78%
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If the ammeter in the given circuit reads 2 A, the resistance R is :

(1) 1 ohm

(2) 2 ohm

(3) 3 ohm

(4) 4 ohm

Subtopic:  Combination of Resistors |
 85%
From NCERT
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Two resistances of 400 Ω and 800 Ω are connected in series with a 6-volt battery of negligible internal resistance. A voltmeter of resistance 10,000 Ω is used to measure the potential difference across 400 Ω. The error in the measurement of potential difference in volts approximately is :

(1) 0.01

(2) 0.02

(3) 0.03

(4) 0.05

Subtopic:  Kirchoff's Voltage Law |
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A galvanometer, having a resistance of 50 Ω gives a full scale deflection for a current of 0.05 A. The length in meter of a resistance wire of area of cross-section 2.97× 10–2 cm2 that can be used to convert the galvanometer into an ammeter which can read a maximum of 5 A current is (Specific resistance of the wire = 5 × 10–7 Ωm

(1) 9

(2) 6

(3) 3

(4) 1.5

Subtopic:  Conversion to Ammeter & Voltmeter |
 74%
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An ammeter reads up to 1 ampere. Its internal resistance is 0.81 ohm. To increase the range to 10 A the value of the required shunt is :

(1) 0.09 Ω

(2) 0.03 Ω

(3) 0.3 Ω

(4) 0.9 Ω

Subtopic:  Conversion to Ammeter & Voltmeter |
 75%
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The length of a wire of a potentiometer is \(100~\text{cm}\), and the emf of its standard cell is \(E\) volt. It is employed to measure the emf of a battery whose internal resistance is \(0.5~\Omega\). If the balance point is obtained at \(l = 30~\text{cm}\) from the positive end, the emf of the battery is:
1. \(\frac{30E}{100}\)
2. \(\frac{30E}{100.5}\)
3. \(\frac{30E}{(100-0.5)}\)
4. \(\frac{30(E-0.5i)}{100}, \) where \(i\) is the current in the potentiometer

Subtopic:  Meter Bridge & Potentiometer |
 57%
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What is the reading of the voltmeter in the following figure?

(1) 3 V

(2) 2 V

(3) 5 V

(4) 4 V

Subtopic:  Combination of Resistors |
 63%
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PMT - 2004
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The current flowing in a coil of resistance \(90~\Omega\) is to be reduced by \(90\%\). What value of resistance should be connected in parallel with it?
1. \(9~\Omega\)
2. \(90~\Omega\)
3. \(1000~\Omega\)
4. \(10~\Omega\)

Subtopic:  Conversion to Ammeter & Voltmeter |
 68%
From NCERT
PMT - 2004
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In a metre bridge experiment, the null point is obtained at 20 cm from one end of the wire when resistance X is balanced against another resistance Y. If X < Y, then where will be the new position of the null point from the same end, if one decides to balance a resistance of 4X against Y 

(1) 50 cm

(2) 80 cm

(3) 40 cm

(4) 70 cm

Subtopic:  Meter Bridge & Potentiometer |
 65%
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