$\begin{array}{ccccc}{\mathrm{CH}}_3& -& \stackrel{{\mathrm{CH}}_3}{\underset{{\mathrm{CH}}_3}{\stackrel{|}{\underset{|}{\mathrm{CH}}}}}& +& {\mathrm{H}}_2\mathrm{C}\end{array}$ = CH₂$\underset{2.5^0\mathrm{C}}{\overset{\mathrm{HF}}{\to }}$(A);    (A) is:

(a) 

(b) 

(c) 

(d) CH₃-$\begin{array}{c}\underset{|}{\mathrm{CH}}\\ {\mathrm{CH}}_3\end{array}$-CH₂-CH=CH₂

Di-imide (N₂H₂) is used to reduce double bond of:

(1)  $-\underset{|}{\mathrm{C}}=\mathrm{O}$               

(2) $-\mathrm{C}\equiv \mathrm{N}$             

(3) -NO₂           

(4) -CH=CH-

End product of the reaction is:-
(a)(b)

(c)      (d)

Product (A) is:-

1.  

2. 

3.  

4. 

Compound (A) is :$$
$$

1.  

2. 

3.  

4. 

MMPP $\to$ Magnesium mono peroxy phthalate. Product (X) is:

1.   

2. 

3.  

4. 

Product (A) is:

(1) Ph-CH₂-Cl                     

(2) Ph-CH₂-Br

(3) Ph-CH₂-CCl₃                 

(4) Ph-CH₂-CBrCl₂

Which one of the following compounds gives acetone (CH₃)₂C=O as one of the products of

1.  

2.  

3. 

4.   

Trans-cyclohexane-1,2-diol can be obtained by the reaction of cyclohexane with:

(1) KMnO₄                                       

(2) OsO₄

(3) peroxy formic acid/H₃O⁺             

(4) SeO₂

$\underset{\left(2\right) {\mathrm{NaBH}}_4, {\mathrm{HO}}^{-}}{\overset{\left(1\right) ({\mathrm{CF}}_2{\mathrm{CO}}_2{)}_2\mathrm{Hg}, {\mathrm{CH}}_3{\mathrm{CH}}_2\mathrm{OH}}{\to }} \underset{(100\%)}{\left(P\right)}$; Product (P) is :

1.  

2.   

3.  

4.