$\underset{2. {\mathrm{NaHSO}}_3}{\overset{1. {\mathrm{OsO}}_4}{\to }}$ Product of the reaction is :

1.    

2. 

3.      

4. 

Addition of OsO₄ to cyclopentene generates:
(1) Achiral product

(2) Racemic product

(3) Meso product

(4) Optically active product

The major product of the following reaction is:

${\mathrm{CH}}_3-\mathrm{CH}={\mathrm{CH}}_2 + \mathrm{HBr} \stackrel{({\mathrm{C}}_6{\mathrm{H}}_5\mathrm{CO}{)}_2{\mathrm{O}}_2}{\to }$

1.  ${\mathrm{CH}}_3-{\mathrm{CH}}_2-{\mathrm{CH}}_2-\mathrm{Br}$

2.  ${\mathrm{CH}}_3\mathrm{CH}\left(\mathrm{Br}\right)-{\mathrm{CH}}_3$

3.  ${\mathrm{BrCH}}_2-\mathrm{CH}={\mathrm{CH}}_2$

4. 

Which series of reactions will achieve the following transformation?

1                          2   

(a) Cl₂/CCl₄         Br₂                           

(b)   HBr             Cl₂/CCl₄

(c) Cl₂/CCl₄         NBS/hv                     

(c)   NBS/hv        Cl₂/CCl₄

The principal organic product formed in the reaction given below is:-

CH₂=CH(CH₂)₈COOH+HBr→...
                                  peroxide

1. CH₃-CHBr(CH₂)₈COOH

2. CH₂=CH(CH₂)₈COBr

3. CH₂BrCH₂(CH₂)₈COOH

4. CH₂=CH(CH₂)₇CHBrCOOH

When 2-butyne is treated with H₂ Pd-BaSO₄, the product formed will be:

1. cis-2-Butene

2. trans-2-Butene

3. 1-Butene

4. 2-Hydroxy butane

 $\underset{Pt}{\overset{H_2}{\to }}$?

The product of the reaction is :

(1) Racemic
(2) Diastereomers
(3) Meso
(4) Pure enantiomers

 cis-2-butene $\underset{\mathrm{Peroxide}}{\overset{\mathrm{HBr}}{\to }}$Product of the reaction is :

(1) Racemic

(2) Diastereomer

(3) Meso

(4) E and Z isomer

      (a)                                  (b)

the correct relation of rate of reaction towards reduction using (H₂/Pt):

1.  a>b

2. a=b

3. b>a

4. Reduction is not possible

Product; Product is:

MCPBA $\to$Metachloroperbenzoic acid

1. 

2. 

3. 

4.