0°CPCl5A70-80%(2) H(1) 3NaNH2, mineral oilB46%; Product (B) is:

Subtopic:  Aliphatic Hydrocarbon - Methods of Preparation | Alkanes, Alkenes and Alkynes - Chemical Properties |
 64%
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Product (K) of the above reaction is:

1. 

2. 
3. 

4. 

Subtopic:  Aliphatic Hydrocarbon - Methods of Preparation |
 61%
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CH3-CH2-CH2-CCH+LiHN2(A)(CH3)2SO4(B)

Give the structural formula of compound (B):

(a) CH3-(CH2)2-CC-SO3H

(b) CH3-(CH2)2-CC-CH3

(c)  CH3-(CH2)2-CC-CH2-O-OsO-H

(d) CH3-CH2-CC-CH2

Subtopic:  Aliphatic Hydrocarbon - Methods of Preparation |
 51%
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The reagents used for the following conversion is/are-

 

1. (i) NaNH2 , (ii) CH3CHO
2. (i) NaNH2 , (ii) CH3-CH2-CH2-Br
3. (i) KOH, (ii) CH3-CH2-CH2-Br
4. (i) KOH, (ii) 

Subtopic:  Aliphatic Hydrocarbon - Methods of Preparation |
 81%
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Which alkyne(s) will yield 3-ethylhexane upon catalytic hydrogenation?
 

1.  2. 
3.  4.  All of the above
Subtopic:  Aliphatic Hydrocarbon - Methods of Preparation |
 66%
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Br-(CH2)12-CCH NaNH2 (A) CatalystLindlar (B); Product (B) is :
1.

2.  
3. 

4. Br-(CH2)12-CH=CH  

Subtopic:  Aliphatic Hydrocarbon - Methods of Preparation |
 64%
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Ph - C CHMeOHMeO- Major product of the reaction is:

(a) 

(b) 

(c) Ph - C C-OMe

(d) 

Subtopic:  Aromatic Hydrocarbons - Benzene - Structure, Preparation & Chemical Reactions |
 70%
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To carry out the above conversion, (A) and (B) respectively are:

1. NaNH2, Cl - CH2ーCH- CH- Br

2. NaNH2, CH2-CH2-CH2-Br

3. NaNH2, l-CH2ーCH2-CH2-Br

4. NaNH2, I-CH2-CH2-CH2-I

Subtopic:  Aliphatic Hydrocarbon - Methods of Preparation |
 56%
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H-CC-Ph   Product; Product obtained in this reaction is:

1.  2. 
3.  \(\mathrm{Ph}-\mathrm{C} \equiv \mathrm{C}-\mathrm{I}\) 4.  \(\mathrm{I}-\mathrm{C} \equiv \mathrm{C}-\mathrm{H}\)
Subtopic:  Aliphatic Hydrocarbon - Methods of Preparation |
 54%
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(ii) CH3Br(i) NaNH2.NH2 (A) Lindiar catalystH2 (B) ; Product (B) is :

1.

2.

3.

4. 

Subtopic:  Aliphatic Hydrocarbon - Methods of Preparation |
 69%
From NCERT
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