Product (B) in this reaction is :

1. 

2.     

3.    

4.    

$\mathrm{Ph}-\stackrel{\stackrel{\mathrm{O}}{\mathrm{ll}}}{\mathrm{C}}-{\mathrm{CH}}_3\underset{\mathrm{HCl}}{\overset{{\mathrm{NaNO}}_2}{\to }}\left(\mathrm{A}\right)\underset{\mathrm{heat}}{\overset{{\mathrm{AC}}_2\mathrm{O}}{\to }}\left(\mathrm{B}\right)\stackrel{{\mathrm{H}}_3{\mathrm{O}}^{+}}{\to }\left(\mathrm{c}\right)$

Product (C) of the above reaction is :

(1) $\mathrm{Ph}-{\mathrm{CO}}_2\mathrm{H}$

(2) $\mathrm{Ph}-\stackrel{\stackrel{\mathrm{O}}{\mathrm{ll}}}{\mathrm{C}}-{\mathrm{CO}}_2\mathrm{H}$

(3) $\mathrm{Ph}-\stackrel{\stackrel{\mathrm{O}}{\mathrm{ll}}}{\mathrm{C}}-\stackrel{\stackrel{\mathrm{O}}{\mathrm{ll}}}{\mathrm{C}}-\mathrm{H}$

(4) $\mathrm{Ph}-\stackrel{\stackrel{\mathrm{O}}{\mathrm{ll}}}{\mathrm{C}}-{\mathrm{CO}}_2\mathrm{H}$

Product (B) of the reaction is :

(1) $\mathrm{Ph}-{\mathrm{CH}}_2-{\mathrm{NO}}_2$

(2) $\mathrm{Ph}-{\mathrm{CH}}_2-\mathrm{ONO}$

(3) $\mathrm{Ph}-\mathrm{CHO}$

(4) $\mathrm{Ph}-\mathrm{O}-\mathrm{N}=\mathrm{O}$

Reactant (A) in this reaction is : 

  (d) Both (b) and (c)

Correct order of reactivity of following compounds towards Grignard reagent ?

${\mathrm{CH}}_3-\stackrel{\stackrel{\mathrm{O}}{\mathrm{ll}}}{\mathrm{C}}-\mathrm{H}$
$\left(\mathrm{I}\right)$          $\mathrm{H}-\stackrel{\stackrel{\mathrm{O}}{\mathrm{ll}}}{\mathrm{C}}-\mathrm{H}$
$\left(\mathrm{II}\right)$

(1) I > II >III

(2) II > I > III

(3) II > III > I

(4) I > III > I

What reagent and/or reaction conditions would you choose to bring about the following conversion?

(a) $1. {\mathrm{LiAlH}}_4, 2. {\mathrm{H}}_2\mathrm{O}$

(b) ${\mathrm{H}}_2\mathrm{O}, {\mathrm{H}}_2{\mathrm{SO}}_4, \mathrm{heat}$

(c) ${\mathrm{H}}_2\mathrm{O}, \mathrm{NaOH}, \mathrm{heat}$

(d) $\mathrm{PCC}, {\mathrm{CH}}_2{\mathrm{Cl}}_2$

\(CH_3-C \equiv CH \xrightarrow [dil. H_2SO_4] {HgSO_4 } (A)\)
\(CH_3-C \equiv CH \xrightarrow [(2) H_2SO_4/HO^-] {(1) BH_3THF} (B)\)
Products (A) and (B) are differentiated by:

1. 2-4 DNP

2. NaOI

3. Na-metal

4. NaHSO₃

End Product (C) in above reaction is :

(b)

(c)

Compound (X) C₄H₈O, which reacts with 2, 4-DNP derivative and gives negative haloform test is.
1. ${\mathrm{CH}}_3-\stackrel{\stackrel{\mathrm{O}}{\mathrm{ll}}}{\mathrm{C}}-{\mathrm{CH}}_2-{\mathrm{CH}}_3$

2. ${\mathrm{CH}}_3-\underset{\underset{{\mathrm{CH}}_3}{\mathrm{l}}}{\mathrm{CH}}-\mathrm{CHO}$

3. 

4. ${\mathrm{CH}}_3-{\mathrm{CH}}_2-\stackrel{\stackrel{\mathrm{OH}}{\mathrm{l}}}{\mathrm{CH}}-{\mathrm{CH}}_3$

Product (B) of the reaction is :

1. 

2. 

3. 

4.