Among the given possible levels of regulation of gene expression:
(i) transcriptional level (formation of primary transcript),
(ii) processing level (regulation of splicing),
(iii) transport of mRNA from nucleus to the cytoplasm,
I: (i) is the predominant site for regulation of gene expression in prokaryotes.
II: (ii) and (iii) are possible only in eukaryotes.
1. Only I is correct
2. Only II is correct
3. Both I and II are correct
4. Both I and II are incorrect
Subtopic: Transcription:II |
84%
Level 1: 80%+
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In a transcription unit, the activity of RNA polymerase at a given promoter is regulated by interaction with accessory proteins called:
1. Enhancers and Silencers
2. Operators and CAP
3. Rho factors and Sigma factors
4. Activators and Repressors
1. Enhancers and Silencers
2. Operators and CAP
3. Rho factors and Sigma factors
4. Activators and Repressors
Subtopic: Transcription:II |
Level 4: Below 35%
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The accessibility of promoter regions of prokaryotic DNA is in many cases regulated by the interaction of
proteins with sequences termed:
1. Enhancers
2. Silencers
3. Operators
4. Terminators
proteins with sequences termed:
1. Enhancers
2. Silencers
3. Operators
4. Terminators
Subtopic: Gene Regulation: Lac Operon |
87%
Level 1: 80%+
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The first to elucidate a transcriptionally regulated system of gene expression were:
1. Jacob and Monod
2. Nirenberg and Khorana
3. Tijo and Levan
4. Beadle and Tatum
1. Jacob and Monod
2. Nirenberg and Khorana
3. Tijo and Levan
4. Beadle and Tatum
Subtopic: Transcription:II |
81%
Level 1: 80%+
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Which of the following statements will be true regarding the effect of mutations in the components of the lac operon of E. coli [assume mutations will lead to loss of function in the affected gene]?
1. Only I and II are correct
2. Only I and III are correct
3. Only II and III are correct
4. I, II and III are correct
| I: | A mutation in the i gene will lead to a stoppage of transcription of the operon. |
| II: | A mutation in the z gene will lead to an inability in E .coli to hydrolyze the disaccharide, lactose. |
| III: | A mutation in the y gene will lead to an inability in E. coli to pick up lactose from its surroundings. |
1. Only I and II are correct
2. Only I and III are correct
3. Only II and III are correct
4. I, II and III are correct
Subtopic: Gene Regulation: Lac Operon |
56%
Level 3: 35%-60%
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Which of the following is synthesised all-the-time – constitutively in E .coli?
1. repressor of the lac operon
2. beta galactosidase
3. permease
4. transacetylase
1. repressor of the lac operon
2. beta galactosidase
3. permease
4. transacetylase
Subtopic: Gene Regulation: Lac Operon |
72%
Level 2: 60%+
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The important goals of HGP included all of the following, except:
| 1. | Identify all the approximately 20,000–25,000 genes in human DNA |
| 2. | Determine the sequences of the 3 billion chemical base pairs that make up human DNA |
| 3. | Develop technology for cloning of human beings |
| 4. | Address the ethical, legal, and social issues (ELSI) that may arise from the project. |
Subtopic: Human Genome Project |
81%
Level 1: 80%+
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Many non-human model organisms have also been sequenced even before sequencing of human genome where:
1. Only I is correct
2. Only II is correct
3. Both I and II are correct
4. Both I and II are incorrect
| I: | Caenorhabditis elegans is a pathogenic nematode |
| II: | Arabidopsis thaliana is a fungus |
1. Only I is correct
2. Only II is correct
3. Both I and II are correct
4. Both I and II are incorrect
Subtopic: Human Genome Project |
51%
Level 3: 35%-60%
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The methodology used in human genome sequencing that took the blind approach of simply sequencing the
whole set of genome that contained all the coding and non-coding sequence, and later assigning different
regions in the sequence with functions, is called as:
1. Expressed sequence tag
2. Sequence annotation
3. Chain termination
4. Physical mapping
whole set of genome that contained all the coding and non-coding sequence, and later assigning different
regions in the sequence with functions, is called as:
1. Expressed sequence tag
2. Sequence annotation
3. Chain termination
4. Physical mapping
Subtopic: Human Genome Project |
83%
Level 1: 80%+
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The last of the 24 human chromosomes – 22 autosomes and X and Y – to be sequenced was:
1. Chromosome 1
2. the X chromosome
3. the Y chromosome
4. Chromosome 22
1. Chromosome 1
2. the X chromosome
3. the Y chromosome
4. Chromosome 22
Subtopic: Human Genome Project |
87%
Level 1: 80%+
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