Q. No.The complex that does not exhibit optical isomerism is:
(en-ethylenediamine)
1. [Co(en)2Cl2]+
2. [Co(NH3)3Cl3]
3. [Co(en)Cl2(NH3)2]+
4. [Co(en)3]3+
(en-ethylenediamine)
Which of the following complex ions is expected to absorb visible light:
(At. no. Zn =30, Sc =21, Ti =22, Cr=24)
1. [Sc(H2O)3(NH3)3]3+
2. [Ti(en)2(NH3)2]4+
3. [Cr(NH3)6]3+
4. [Zn(NH3)6]2+
Which of the following complexes exhibits the highest paramagnetic behaviour?
where gly = glycine, en = ethylenediamine and bpy = bipyridyl moieties
(At no : Ti = 22, V = 23, Fe= 26, Co = 27)
(1) [V(gly)2 (OH)2(NH3)2]+
(2) [Fe(en)(bpy)NH3)2]2+
(3) [Co(OX)2(OH)2]-
(4) [Ti(NH3)6]3+
∆oct(CFSE in the octahedral field) will be maximum in:
(Atomic number Co = 27)
1. [Co(H2O)6]3+
2. [Co(NH3)6]3+
3. [Co(CN)6]3
4. [Co(C2O4)3]3
Which of the following will give a pair of enantiomorphs?
(1) [Co(NH3)4Cl2]NO2
(2) [Cr(NH3)6][Co(CN)6]
(3) [Co(en)2Cl2]CI
(4) [Pt(NH3)4][PtCl6 ]
(en =NH2CH2CH2NH2)
Copper sulphate dissolves in excess of KCN to give :
(1) CuCN
(2) [Cu(CN)4]3-
(3) [Cu(CN4]2-
(4) Cu(CN)2
[Co(NH3)4(NO2)2]Cl can show:
| 1. | Linkage isomerism, ionization isomerism and optical isomerism. |
| 2. | Linkage isomerism, ionization isomerism and geometrical isomerism. |
| 3. | Ionisation isomerism, geometrical isomerism and optical isomerism. |
| 4. | Ionisation isomerism, geometrical isomerism and optical isomerism. |
The existence of two different coloured complexes with the composition of
[Co(NH3)4Cl2]+ is due to :-
1. linkage isomerism
2. geometrical isomerism
3. coordination isomerism
4. ionisation isomerism
Which of the following complex ions is not expected to absorb visible light ?
1. [Ni(CN)4]2-
2. [Cr(NH3)6]3+
3. [Fe(H2O)6]2+
4. [Ni(H2O)6]2+
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