If two people who are carrier for a genetically inherited fatal recessive disease decide to marry and disease cause still birth. What is the probability of the live children to be a carrier?

a.1/2

b.2/3

c.1/4

d.1/3

Subtopic:  Pedigree Analysis: Problem Solving |
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Assertion : Phenylketonuria is a recessive hereditary disease caused by the body’s failure to oxidize an amino acid phenylalanine to tyrosine, because of a defective enzyme.

Reason : It results in the presence of phenylalanine acid in the urine.

  1. If both the assertion and the reason are true and the reason is a correct explanation of the assertion
  2. If both the assertion and reason are true but the reason is not a correct explanation of the assertion
  3. If the assertion is true but the reason is false
  4. If both the assertion and reason are false
Subtopic:  Mendelian Disorders |
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Assertion   :       In honey bee, life history shows natural and complete parthenogenesis.

Reason      :       In honey bee, both drones and workers are parthenogenetically developed.

  1. If both the assertion and the reason are true and the reason is a correct explanation of the assertion
  2. If both the assertion and reason are true but the reason is not a correct explanation of the assertion
  3. If the assertion is true but the reason is false
  4. If both the assertion and reason are false
Subtopic:  Sex Determination |
 54%
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A plant, on repeated self pollination, preserves the trait expressed for many generations. Such a plant is said to be:

(1) Panmictic

(2) Homologous

(3) Apomictic                                                

(4) Pure line

Subtopic:  Monohybrid Cross: 1 |
 84%
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The F1 progeny in monohybrid crosses by Mendel resembled:

1. The parent exhibiting dominant trait completely

2. The parent exhibiting recessive trait completely

3. The parent exhibiting dominant trait partly

4. The parent exhibiting recessive trait partly

Subtopic:  Monohybrid Cross: 1 |
 82%
From NCERT
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In a true breeding the allelic pair of genes are

1. Homologous
2. Linked
3. Stable
4. Homozygous

Subtopic:  Monohybrid Cross: 1 |
 58%
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A test cross is done to find out:

(1) Fitness of an organism

(2) Genotype of a plant expressing dominant phenotype

(3) The suitable parents for a Mendelian Cross

(4) The hidden genotypic ratio of F2 phenotypes

Subtopic:  Monohybrid Cross: Further Understanding |
 82%
From NCERT
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What is the ratio of a typical monohybrid test cross?

(1) 2 : 1

(2) 3 : 1

(3) 1: 2 : 1                

(4) 1 : 1

Subtopic:  Monohybrid Cross: 1 |
 65%
From NCERT
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The law of Segregation is based on the fact that

1. The alleles do not show any blending

2. There is random fertilization

3. Gametes are pure for the trait

4. The zygotes are diploid

Subtopic:  Law of Segregation |
 82%
From NCERT
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The inheritance of flower colour in dog flower and 4’O clock plant exhibits:

1. Complete dominance

2. Incomplete dominance

3. Co-dominance

4. Lethality

Subtopic:  Dominance Deviation from Mendel: 1 |
 93%
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