Eight dipoles of charges of magnitude \((e)\) are placed inside a cube. The total electric flux coming out of the cube will be: 
1. \(\frac{8e}{\epsilon _{0}}\)
2. \(\frac{16e}{\epsilon _{0}}\)
3. \(\frac{e}{\epsilon _{0}}\)
4. zero

Subtopic:  Electric Dipole |
 76%
From NCERT
PMT - 1998
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A charge q is placed at the centre of the open end of the cylindrical vessel. The flux of the electric field through the surface of the vessel is 

(1) Zero

(2) qε0

(3) q2ε0

(4) 2qε0 

Subtopic:  Gauss's Law |
 50%
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\(q_1, q_2,q_3~\text{and}~q_4\) are point charges located at points as shown in the figure and \(S\) is a spherical Gaussian surface of radius \(R\). Which of the following is true according to the Gauss’s law?


1. \(\oint_s\left(\vec{E}_1+\vec{E}_2+\vec{E}_3\right) \cdot d \vec{A}=\frac{q_1+q_2+q_3}{2 \varepsilon_0}\)
2. \(\oint_s\left(\vec{E}_1+\vec{E}_2+\vec{E}_3+\vec{E}_4\right) \cdot d \vec{A}=\frac{\left(q_1+q_2+q_3\right)}{\varepsilon_0}\)
3. \(\oint_s\left(\vec{E}_1+\vec{E}_2+\vec{E}_3\right) \cdot d \vec{A}=\frac{\left(q_1+q_2+q_3+q_4\right)}{\varepsilon_0}\)
4. \(\oint_s\left(\vec{E}_1+\vec{E}_2+\vec{E}_3+\vec{E}_4\right) \cdot d \vec{A}=\frac{\left(q_1+q_2+q_3+q_4\right)}{\varepsilon_0}\)

Subtopic:  Gauss's Law |
 77%
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Consider the charge configuration and spherical Gaussian surface as shown in the figure. While calculating the flux of the electric field over the spherical surface, the electric field will be due to: 

(1) q2 only

(2) Only the positive charges

(3) All the charges

(4) +q1 and – q1 only

Subtopic:  Gauss's Law |
 61%
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The electric intensity due to an infinite cylinder of radius R and having charge q per unit length at a distance r(r > R) from its axis is 

(1) Directly proportional to r2

(2) Directly proportional to r3

(3) Inversely proportional to r

(4) Inversely proportional to r2

Subtopic:  Electric Field |
 66%
From NCERT
PMT - 1993
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Two infinitely long parallel wires having linear charge densities λ1 and λ2 respectively are placed at a distance of R meters. The force per unit length on either wire will be K=14πε0

(1) K2λ1λ2R2

(2) K2λ1λ2R

(3) Kλ1λ2R2 

(4) Kλ1λ2R

Subtopic:  Electric Field |
 60%
From NCERT
PMT - 1998
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Charge q is uniformly distributed over a thin half-ring of radius R. The electric field at the centre of the ring is 

(1) q2π2ε0R2

(2) q4π2ε0R2 

(3) q4πε0R2

(4) q2πε0R2

Subtopic:  Electric Field | Gauss's Law |
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Three positive charges of equal value q are placed at the vertices of an equilateral triangle. The resulting lines of force should be sketched as in 

(1)   (2)

(3)    (4)

Subtopic:  Electric Field |
 76%
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An infinite number of electric charges each equal to \(5\) nC (magnitude) are placed along the \(x\text-\)axis at \(x=1\) cm, \(x=2\) cm, \(x=4\) cm, \(x=8\) cm ………. and so on. In the setup if the consecutive charges have opposite sign, then the electric field in Newton/Coulomb at \(x=0\) is: \(\left(\frac{1}{4 \pi \varepsilon_{0}} = 9 \times10^{9} ~\text{N-m}^{2}/\text{C}^{2}\right)\)
1. \(12\times 10^{4}\)
2. \(24\times 10^{4}\)
3. \(36\times 10^{4}\)
4. \(48\times 10^{4}\)

Subtopic:  Electric Field |
 58%
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Two-point charges \(+q\) and \(–q\) are held fixed at \((–d, 0)\) and \((d, 0)\) respectively of a \((x, y)\) coordinate system. Then:

1. \(E\) at all points on the \(y\text-\)axis is along \(\hat i\)
2. The electric field \(\vec E \) at all points on the \(x\text-\)axis has the same direction
3. The dipole moment is \(2qd\) directed along \(\hat i\)
4. The work has to be done to bring a test charge from infinity to the origin

Subtopic:  Electric Dipole |
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