A point charge \(q\) is placed at a distance \(\frac{a}{2}\) directly above the centre of a square of side \(a\). The electric flux through the square (i.e. one face) is:
1. \(\frac{q}{\varepsilon_0}\)
2. \(\frac{q}{\pi\varepsilon_0}\)
3. \(\frac{q}{4\varepsilon_0}\)
4. \(\frac{q}{6\varepsilon_0}\)

Subtopic:  Gauss's Law |
 62%
From NCERT
PMT - 1997
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Two infinitely long parallel wires having linear charge densities λ1 and λ2 respectively are placed at a distance of R meters. The force per unit length on either wire will be K=14πε0

(1) K2λ1λ2R2

(2) K2λ1λ2R

(3) Kλ1λ2R2 

(4) Kλ1λ2R

Subtopic:  Electric Field |
 59%
From NCERT
PMT - 1998
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The charge on 500 cc of water due to protons will be:

1. 6.0 × 1027 C
2. 2.67 × 107 C
3. 6 × 1023 C
4. 1.67 × 1023 C

Subtopic:  Electric Charge |
 62%
From NCERT
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In the given figure two tiny conducting balls of identical mass m and identical charge q hang from non-conducting threads of equal length L. Assume that θ is so small that tanθsinθ, then for equilibrium x is equal to 

(1) q2L2πε0mg13

(2) qL22πε0mg13

(3) q2L24πε0mg13

(4) q2L4πε0mg13

Subtopic:  Coulomb's Law |
 59%
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Three positive charges of equal value q are placed at the vertices of an equilateral triangle. The resulting lines of force should be sketched as in 

(1)   (2)

(3)    (4)

Subtopic:  Electric Field |
 76%
From NCERT
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Two equal charges are separated by a distance d. A third charge placed on a perpendicular bisector at x distance will experience maximum coulomb force when 

(1) x=d2

(2) x=d2

(3) x=d22

(4) x=d23

Subtopic:  Coulomb's Law |
From NCERT
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An electric dipole is situated in an electric field of uniform intensity E whose dipole moment is p and moment of inertia is I. If the dipole is displaced slightly from the equilibrium position, then the angular frequency of its oscillations is?

1. pEI1/2

2. pEI3/2

3. IpE1/2

4. pIE1/2

Subtopic:  Electric Dipole |
 70%
From NCERT
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An infinite number of electric charges each equal to \(5\) nC (magnitude) are placed along the \(x\text-\)axis at \(x=1\) cm, \(x=2\) cm, \(x=4\) cm, \(x=8\) cm ………. and so on. In the setup if the consecutive charges have opposite sign, then the electric field in Newton/Coulomb at \(x=0\) is: \(\left(\frac{1}{4 \pi \varepsilon_{0}} = 9 \times10^{9} ~\text{N-m}^{2}/\text{C}^{2}\right)\)
1. \(12\times 10^{4}\)
2. \(24\times 10^{4}\)
3. \(36\times 10^{4}\)
4. \(48\times 10^{4}\)

Subtopic:  Electric Field |
 58%
From NCERT
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Three charges –q1, +q2 and –q3 are placed as shown in the figure. The x-component of the force on –q1 is proportional to 

(1) q2b2q3a2sinθ

(2) q2b2q3a2cosθ

(3) q2b2+q3a2sinθ

(4) q2b2+q3a2cosθ

Subtopic:  Coulomb's Law |
 56%
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Two-point charges \(+q\) and \(–q\) are held fixed at \((–d, 0)\) and \((d, 0)\) respectively of a \((x, y)\) coordinate system. Then:

1. \(E\) at all points on the \(y\text-\)axis is along \(\hat i\)
2. The electric field \(\vec E \) at all points on the \(x\text-\)axis has the same direction
3. The dipole moment is \(2qd\) directed along \(\hat i\)
4. The work has to be done to bring a test charge from infinity to the origin

Subtopic:  Electric Dipole |
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