If g is the acceleration due to gravity on the earth's surface, the gain in the potential energy of an object of mass m raised from the surface of earth to a height equal to the radius of the earth R, is
1. 12mgR12mgR
2. 2 mgR
3. mgR
4. 14mgR14mgR
Weightlessness experienced while orbiting the earth in a space-ship is the result of:
1. Inertia
2. Acceleration
3. Zero gravity
4. Freefall towards the earth
The escape velocity for a rocket from the earth is 11.211.2 km/s. Its value on a planet where the acceleration due to gravity is double that on the earth and the diameter of the planet is twice that of the earth (in km/s) will be:
1. | 11.211.2 | 2. | 5.65.6 |
3. | 22.422.4 | 4. | 53.653.6 |
The escape velocity from the earth is about 11 km/second. The escape velocity from a planet having twice the radius and the same mean density as the earth is
1. 22 km/sec
2. 11 km/sec
3. 5.5 km/sec
4. 15.5 km/sec
What should be the velocity of earth due to rotation about its own axis so that the weight at equator become 3/5 of initial value. Radius of earth on equator is 6400 km
1. 7.4×10-47.4×10−4 rad/sac
2. 6.4×10-4×10−4 rad/sac
3. 7.8×10-47.8×10−4 rad/sac
4. 8.7×10-4×10−4 rad/sac
If g is the acceleration due to gravity at the earth's surface and r is the radius of the earth, the escape velocity for the body to escape out of the earth's gravitational field is:
1. gr
2. √2gr√2gr
3. g/r
4. r/g
The escape velocity of a projectile from the earth is approximately
1. 11.2 m/sec 2. 112 km/sec
3. 11.2 km/sec 4. 11200 km/sec
The escape velocity of a particle of mass m varies as:
1. m2m2
2. m
3. m0m0
4. m-1m−1
Acceleration due to gravity is ‘g’ on the surface of the earth. The value of acceleration due to gravity at a height of 32 km above earth’s surface is (Radius of the earth = 6400 km)
1. 0.9 g
2. 0.99 g
3. 0.8 g
4. 1.01 g
The time period of a simple pendulum on a freely moving artificial satellite is
1. Zero
2. 2 sec
3. 3 sec
4. Infinite