If Hershey and Chase had found 'S in both the pellet and the supernatant, the conclusion about the nature of DNA replication would be that:
(1) Protein must be the information molecule

(2) It would be difficult to conclude anything from these results

(3) DNA is the genetic information molecule

(4) Phage must have stuck to the bacteria

Experiments by Avery, Macleod, and McCarty supported DNA as the genetic material by showing that:
(1) Both protein and DNA samples provided the transforming factor

(2) DNA was not complex enough to be the genetic material

(3) Only samples with DNA provided transforming activity

(4) Even though DNA was molecularly simple, it provided adequate variation to act as the genetic material

What are the mini-satellites?

(1) r-DNA             

(2) VNTR              

(3) c-DNA             

(4) SAT

Which statement about complementary base pairing is not true?
(1) It plays a role in DNA replication

(2) In DNA, T pairs with A

(3) Purines pair with purines, and pyrimidines pair with pyrimidines

(4) In DNA, C pairs with G

Western Blot hybridization is used for:

(1) DNA analysis                               

(2) RNA analysis

(3) Protein analysis                             

(4) Polysaccharide analysis

SNP which is pronounced as "snips” stands for:

(1) Small nuclear protein                   

(2) Single nucleotide particle

(3) Single nucleotide polymorphism   

(4) Small nicking points

The length of E. coli DNA and length of DNA in a human 2N cell is:

(1) 1.36 mm and 2.2 m respectively  

(2) 1.36 mm and 2.2 mm respectively

(3) 1.3 ìm and 2.2 ìm respectively    

(4) 1.36 cm and 2.2 cm respectively

Escherichia coli cells were grown for many generations in ¹⁵NH₄Cl as sole nitrogen source. Subsequently, these cells were grown exactly for four generations in medium containing ¹⁴NH₄Cl. The DNA from these cells were isolated and separated. If ¹⁵N/¹⁵N represents the two strands of DNA where both strands have heavy nitrogen; ¹⁵N/¹⁴N as intermediate DNA; and ¹⁴N/¹⁴N as DNA containing light nitrogen, the ratios for heavy: intermediate: light DNA, respectively would be:

(1) 1 : 0 : 7         

(2) 1 : 1 : 6         

(3) 0 : 1 : 7          

(4) 0 : 8 : 0

Match each item in COLUMN I with one in COLUMN II and select your answer from the codes given:

Codes:
    A.    B.    C.     D.
1. c      a     d      b
2. c      a     b      d
3. a      b     c      d
4. a      c     d      b       

The base pairing in a double stranded DNA is correctly described as: