In an LR-circuit, the inductive reactance is equal to the resistance R of the circuit. An e.m.f. E=E0cos(ωt) applied to the circuit. The power consumed in the circuit is:

(1) E02R

(2) E022R

(3) E024R

(4) E028R

Subtopic:  Different Types of AC Circuits |
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One 10 V, 60 W bulb is to be connected to 100 V line. The required induction coil has a self-inductance of value: (f = 50 Hz) 

(1) 0.052 H

(2) 2.42 H

(3) 16.2 mH

(4) 1.62 mH

Subtopic:  Different Types of AC Circuits |
 56%
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In the circuit given below, what will be the reading of the voltmeter 

(1) 300 V

(2) 900 V

(3) 200 V

(4) 400 V

Subtopic:  Different Types of AC Circuits |
 91%
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In the circuit shown below, what will be the readings of the voltmeter and ammeter?
             

1. \(800~\text{V}, 2~\text{A}\)
2. \(300~\text{V}, 2~\text{A}\)
3. \(220~\text{V}, 2.2~\text{A}\)
4. \(100~\text{V}, 2~\text{A}\)

Subtopic:  Different Types of AC Circuits |
 88%
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The diagram shows a capacitor C and a resistor R connected in series to an ac source. V1 and V2 are voltmeters and A is an ammeter:

Consider now the following statements

I. Readings in A and V2 are always in phase

II. Reading in V1 is ahead in phase with reading in V2

III. Readings in A and V1 are always in phase

Which of these statements is/are correct?

(1) I only

(2) II only

(3) I and II only

(4) II and III only

Subtopic:  Different Types of AC Circuits |
 57%
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In the circuit shown in figure neglecting source resistance the voltmeter and ammeter reading will respectively, will be 

(1) 0V, 3A

(2) 150V, 3A

(3) 150V, 6A

(4) 0V, 8A

Subtopic:  Different Types of AC Circuits |
 86%
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In the circuit shown in the figure, the ac source gives a voltage V=20cos(2000 ​t). Neglecting source resistance, the voltmeter and ammeter reading will be: 

(1) 0V, 0.47A

(2) 1.68V, 0.47A

(3) 0V, 1.4 A

(4) 5.6V, 1.4 A

Subtopic:  RMS & Average Values |
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An ac source of angular frequency \(\omega\) is fed across a resistor \(r\) and a capacitor \(C\) in series. \(I\) is the current in the circuit. If the frequency of the source is changed to \(\frac{\omega}{3}\) (but maintaining the same voltage), the current in the circuit is found to be halved. Calculate the ratio of reactance to resistance at the original frequency \(\omega\).

1. \(\sqrt{\dfrac{3}{5}}\) 2. \(\sqrt{\dfrac{2}{5}}\)
3. \(\sqrt{\dfrac{1}{5}}\) 4. \(\sqrt{\dfrac{4}{5}}\)
Subtopic:  Different Types of AC Circuits |
 64%
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For a series \(RLC\) circuit, \(R = X_L = 2X_C.\) The impedance of the circuit and phase difference between \(V\) and \(i\) will be: 
1. \(\frac{\sqrt{5} R}{2} ,\tan^{- 1} \left(2\right)\) 2. \(\frac{\sqrt{5} R}{2} , \tan^{- 1} \left(\frac{1}{2}\right)\)
3. \(\sqrt{5} X_{C} ,\tan^{- 1} \left(2\right)\) 4. \(\sqrt{5} R , \tan^{- 1} \left(\frac{1}{2}\right)\)
Subtopic:  Different Types of AC Circuits |
 72%
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In the adjoining ac circuit the voltmeter whose reading will be zero at resonance is

(1) V1

(2) V2

(3) V3

(4) V4

Subtopic:  Different Types of AC Circuits |
 85%
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