If there are n capacitors each of capacitance C in parallel connected to V volt source, then the energy stored is equal to 

1. CV

2. 12nCV2

3. CV2

4. 12nCV2

Subtopic:  Energy stored in Capacitor |
 92%
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The unit of electric permittivity is 

(1) Volt/m2

(2) Joule/coulomb

(3) Farad/m

(4) Henry/m

Subtopic:  Capacitance |
 65%
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A parallel plate capacitor of capacity \(C_0\) is charged to a potential \(V_0\)
(i) The energy stored in the capacitor when the battery is disconnected and the separation is doubled is \(E_1\)
(ii) The energy stored in the capacitor when the charging battery is kept connected and the separation between the capacitor plates is doubled is \(E_2\).
Then \(\frac{E_1}{E_2}\) value is:
1. \(4\)
2. \(\frac{3}{2}\)
3. \(2\)
4. \(\frac{1}{2}\)
Subtopic:  Energy stored in Capacitor |
 61%
From NCERT
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Two identical capacitors are joined in parallel, charged to a potential V and then separated and then connected in series i.e. the positive plate of one is connected to negative of the other 

(1) The charges on the free plates are destroyed

(2) The charges on the free plates are enhanced

(3) The energy stored in the system increases

(4) The potential difference in the free plates becomes 2V

Subtopic:  Combination of Capacitors |
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A parallel plate capacitor is made by stacking n equally spaced plates connected alternately. If the capacitance between any two plates is C then the resultant capacitance is

(1) C

(2) nC

(3) (n – 1)C

(4) (n + 1)C

Subtopic:  Combination of Capacitors |
 68%
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Four plates of equal area A are separated by equal distances d and are arranged as shown in the figure. The equivalent capacity is

(1) 2ε0Ad

(2) 3ε0Ad

(3) 4ε0Ad

(4) ε0Ad

Subtopic:  Combination of Capacitors |
 65%
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A parallel plate capacitor with air as medium between the plates has a capacitance of 10 μF. The area of capacitor is divided into two equal halves and filled with two media as shown in the figure having dielectric constant k1 = 2 and k2 = 4. The capacitance of the system will now be 

(1) 10 μF

(2) 20 μF

(3) 30 μF

(4) 40 μF

Subtopic:  Dielectrics in Capacitors |
 80%
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Three capacitors are connected to D.C. source of 100 volts shown in the adjoining figure. If the charge accumulated on plates of C1, C2 and C3 are qa,qb,qc,qd.qe and qf respectively, then 

(1) qb+qd+qf=1009C

(2) qb+qd+qf=0

(3) qa+qc+qe=50C

(4) qb=qd=qf

Subtopic:  Combination of Capacitors |
 68%
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n identical condensers are joined in parallel and are charged to potential V. Now they are separated and joined in series. Then the total energy and potential difference of the combination will be 

(1) Energy and potential difference remain the same

(2) Energy remains the same and the potential difference is nV

(3) Energy increases n times and potential difference is nV

(4) Energy increases n times and potential difference remains the same

Subtopic:  Energy stored in Capacitor |
 54%
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Five capacitors of 10 μF capacity each are connected to a d.c. potential of 100 volts as shown in the adjoining figure. The equivalent capacitance between the points A and B will be equal to 

(1) 40 μF

(2) 20 μF

(3) 30 μF

(4) 10 μF

Subtopic:  Combination of Capacitors |
 88%
From NCERT
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