Weightlessness experienced while orbiting the earth in a space-ship is the result of:
1. Inertia
2. Acceleration
3. Zero gravity
4. Freefall towards the earth
The escape velocity for a rocket from the earth is \(11.2\) km/s. Its value on a planet where the acceleration due to gravity is double that on the earth and the diameter of the planet is twice that of the earth (in km/s) will be:
1. | \(11.2\) | 2. | \(5.6\) |
3. | \(22.4\) | 4. | \(53.6\) |
If g is the acceleration due to gravity at the earth's surface and r is the radius of the earth, the escape velocity for the body to escape out of the earth's gravitational field is:
(1) gr
(2)
(3) g/r
(4) r/g
The escape velocity of a particle of mass m varies as:
(1)
(2) m
(3)
(4)
The time period of a simple pendulum on a freely moving artificial satellite is
(1) Zero
(2) 2 sec
(3) 3 sec
(4) Infinite
The escape velocity of an object from the earth depends upon the mass of the earth (M), its mean density, its radius (R) and the gravitational constant (G). Thus the formula for escape velocity is:
(1)
(2)
(3)
(4)
If radius of earth is R then the height h’ at which value of ‘g’ becomes one-fourth is
(1)
(2)
(3)R
(4)
Assume that the acceleration due to gravity on the surface of the moon is 0.2 times the acceleration due to gravity on the surface of the earth. If is the maximum range of a projectile on the earth’s surface, what is the maximum range on the surface of the moon for the same velocity of projection ?
(a) 0.2
(b) 2
(c) 0.5
(d) 5
1. | Its mass increases |
2. | Its mass decreases |
3. | Its weight increases |
4. | Its weight decreases |
How many times is escape velocity, of orbital velocity for a satellite revolving near earth?
(a) times (b) 2 times
(c) 3 times (d) 4 times