The escape velocity on earth is 11.2 km/s. On another planet having twice radius and 8 times mass of the earth, the escape velocity will be
1. 3.7 km/s 2. 11.2 km/s
3. 22.4 km/s 4. 43.2 km/s
When a body is taken from the equator to the poles, its weight
1. Remains constant
2. Increases
3. Decreases
4. Increases at N-pole and decreases at S-pole
The escape velocity of a body on the surface of the earth is 11.2 km/s. If the earth's mass increases to twice its present value and the radius of the earth becomes half, the escape velocity would become
1. 5.6 km/s
2. 11.2 km/s (remain unchanged)
3. 22.4 km/s
4. 44.8 km/s
1. | Its mass increases |
2. | Its mass decreases |
3. | Its weight increases |
4. | Its weight decreases |
Given mass of the moon is 1/81 of the mass of the earth and corresponding radius is 1/4 of the earth. If escape velocity on the earth surface is 11.2 km/s, the value of same on the surface of the moon is
1. 0.14 km/s
2. 0.5 km/s
3. 2.5 km/s
4. 5 km/s
The angular velocity of rotation of star (of mass M and radius R) at which the matter start to escape from its equator will be
1.
2.
3.
4.
A body weighs 700 gm wt on the surface of the earth. How much will it weigh on the surface of a planet whose mass of earth's mass and radius is half that of the earth ?
1. 200 gm wt
2. 400 gm wt
3. 50 gm wt
4. 300 gm wt
What will be the acceleration due to gravity at height h if h >> R where R is radius of earth and g is acceleration due to gravity on the surface of earth ?
1.
2.
3.
4.
How many times is escape velocity, of orbital velocity for a satellite revolving near earth?
1. times
2. 2 times
3. 3 times
4. 4 times
The acceleration due to gravity near the surface of a planet of radius R and density d is
proportional to
1.
2.
3. dR
4.