When a body is taken from the equator to the poles, its weight
(1) Remains constant
(2) Increases
(3) Decreases
(4) Increases at N-pole and decreases at S-pole
The escape velocity of a body on the surface of the earth is 11.2 km/s. If the earth's mass increases to twice its present value and the radius of the earth becomes half, the escape velocity would become
(1) 5.6 km/s
(2) 11.2 km/s (remain unchanged)
(3) 22.4 km/s
(4) 44.8 km/s
1. | Its mass increases |
2. | Its mass decreases |
3. | Its weight increases |
4. | Its weight decreases |
Given mass of the moon is 1/81 of the mass of the earth and corresponding radius is 1/4 of the earth. If escape velocity on the earth surface is 11.2 km/s, the value of same on the surface of the moon is
(1)0.14 km/s (2)0.5 km/s
(3)2.5 km/s (4)5 km/s
The angular velocity of rotation of star (of mass M and radius R) at which the matter start to escape from its equator will be
(1)
(2)
(3)
(4)
A body weighs 700 gm wt on the surface of the earth. How much will it weigh on the surface of a planet whose mass of earth's mass and radius is half that of the earth ?
(1) 200 gm wt
(2) 400 gm wt
(3) 50 gm wt
(4) 300 gm wt
What will be the acceleration due to gravity at height h if h >> R where R is radius of earth and g is acceleration due to gravity on the surface of earth ?
(1)
(2)
(3)
(4)
How many times is escape velocity, of orbital velocity for a satellite revolving near earth?
(a) times (b) 2 times
(c) 3 times (d) 4 times
The acceleration due to gravity near the surface of a planet of radius R and density d is
proportional to
1.
2.
3. dR
4.
The weight of a body at the centre of the earth is -
1. Zero
2. Infinite
3. Same as on the surface of the earth
4. None of the above