An earth satellite of mass m revolves in a circular orbit at a height h from the surface of

the earth. R is the radius of the earth and g is acceleration due to gravity at the surface

of the earth. The velocity of the satellite in the orbit is given by:

1. $\frac{g{R}^2}{R+h}$                     

2. gR

3. $\frac{gR}{R+h}$                     

4. $\sqrt{\frac{g{R}^2}{R+h}}$

A satellite which is geostationary in a particular orbit is taken to another orbit. Its

distance from the centre of earth in new orbit is 2 times that of the earlier orbit. The time

period in the second orbit is:

1. 4.8 hours                         

2. $48\sqrt{2}$ hours

3. 24 hours                           

4. $24\sqrt{2}$ hours

The ratio of the K.E. required to be given to the satellite to escape earth's gravitational

field to the K.E. required to be given so that the satellite moves in a circular orbit just

above earth atmosphere is:

1. One                           

2. Two

3. Half                           

4. Infinity

An astronaut orbiting the earth in a circular orbit 120 km above the surface of earth, gently drops a spoon out of space-ship. The spoon will

1. Fall vertically down to the earth

3. Move towards the moon

4. Will move along with space-ship

4. Will move in an irregular way then fall down

The period of a satellite in a circular orbit around a planet is independent of 

1. The mass of the planet

2. The orbital radius of satellite  around the planet

3. The mass of the satellite

4. All the three parameters 1, 2 and 3

A geostationary satellite:

1. Revolves about the polar axis

2. Has a time period less than that of the near-earth satellite

3. Moves faster than a near-earth satellite

4. Is stationary in the space

A small satellite is revolving near earth's surface. Its orbital velocity will be nearly

(1) 8 km/sec                       

(2) 11.2 km/sec

(3) 4 km/sec                       

(4) 6 km/sec

The distance of neptune and saturn from sun are nearly ${10}^{13}$ and ${10}^{12}$ meters respectively. Assuming that they move in circular orbits, their periodic times will be in the ratio

(1) $\sqrt{10}$                                               

(2) 100

(3) $10\sqrt{10}$                                             

(4) $1/\sqrt{10}$ 

The orbital velocity of an artificial satellite in a circular orbit just above the earth's surface is v. For a satellite orbiting at an altitude of half of the earth's radius, the orbital velocity is

(1) $\frac{3}{2}v$                     

(2) $\sqrt{\frac{3}{2}}v$

(3) $\sqrt{\frac{2}{3}}v$                   

(4) $\frac{2}{3}v$

In a satellite if the time of revolution is T, then K.E. is proportional to 

(1) $\frac{1}{T}$                       

(2) $\frac{1}{T^2}$

(3) $\frac{1}{T^3}$                       

(4) $T^{\raisebox{1ex}{$-2$}\!\left/ \!\raisebox{-1ex}{$3$}\right.}$