If the radius of the earth contracts by 2% and its mass remains the same, then weight of the body at the earth surface :

1.  Will decrease                      

2.  Will increase

3.  Will remain the same             

4.  None of these

The kinetic energy needed to project a body of mass m from the earth surface (radius R) to infinity is -

1.   mgR/2                 

2.  2 mgR

3.   mgR                   

4.   mgR/4

A satellite is to revolve round the earth in a circle of radius 8000 km. The speed at which this satellite be projected into an orbit, will be 
1. $3 km/s$                     

2. 16 km/s

3. 7.15 km/s                   

4. 8 km/s

If the mass of a body is M on the earth surface, then the mass of the same body on the moon surface is:

1.  M/6       
2.  Zero
3.  M         
4.  None of these

Radius of orbit of satellite of earth is R. Its kinetic energy is proportional to -

1. $\frac{1}{R}$                      

2. $\frac{1}{\sqrt{R}}$

3. R                         

4.  $\frac{1}{R^{3/2}}$

A particle falls towards earth from infinity. It’s velocity on reaching the earth would be -

1.   Infinity                   

2. $\sqrt{2gR}$

3.  $2\sqrt{gR}$                   

4.  Zero

Two satellite A and B, ratio of masses 3 : 1 are in circular orbits of radii r and 4r. Then ratio of total mechanical energy of A to B is 

1. 1 : 3                             

2. 3 : 1

3. 3 : 4                             

4. 12 : 1

The orbital velocity of a planet revolving close to earth's surface is 

1. $\sqrt{2gR}$              

2. $\sqrt{gR}$

3. $\sqrt{\frac{2g}{R}}$               

4. $\sqrt{\frac{g}{R}}$  

If the gravitational force between two objects were proportional to $\frac{1}{R}$ (and not as$\frac{1}{R^2}$) where $R$ is the separation between them, then a particle in circular orbit under such a force would have its orbital speed $v$ proportional to:
1. $\frac{1}{R^2}$
2. $R^{0}$
3. $R^{1}$
4. $\frac{1}{R}$