A particle executes linear simple harmonic motion with an amplitude of of 3 cm. When the particle is at 2 cm from the mean position, the magnitude of its velocity  is equal to that of its acceleration. Then, its time period in seconds is 

1. 5π

2.52π

3. 4π5

4. 2π3

Subtopic:  Simple Harmonic Motion |
 77%
From NCERT
NEET - 2017
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A spring of force constant \(k\) is cut into lengths of ratio \(1:2:3\). They are connected in series and the new force constant is \(k'\). Then they are connected in parallel and the force constant is \(k''\). Then \(k':k''\) is:
1. \(1:9\)
2. \(1:11\)
3. \(1:14\)
4. \(1:6\)

Subtopic:  Combination of Springs |
 72%
From NCERT
NEET - 2017
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A body of mass \(m\) is attached to the lower end of a spring whose upper end is fixed. The spring has negligible mass. When the mass \(m\) is slightly pulled down and released, it oscillates with a time period of \(3~\text{s}\). When the mass \(m\) is increased by \(1~\text{kg}\), the time period of oscillations becomes \(5~\text{s}\). The value of \(m\) in \(\text{kg}\) is:
1. \(\dfrac{3}{4}\)

2. \(\dfrac{4}{3}\)

3. \(\dfrac{16}{9}\)

4. \(\dfrac{9}{16}\)

Subtopic:  Spring mass system |
 83%
From NCERT
NEET - 2016
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A particle executes linear simple harmonic motion with amplitude of \(3~\text{cm}\). When the particle is at \(2~\text{cm}\) from the mean position, the magnitude of its velocity is equal to that of its acceleration. Then its time period in seconds is:
1. \(\frac{\sqrt5}{2\pi}\)
2. \(\frac{4\pi}{\sqrt5}\)
3. \(\frac{4\pi}{\sqrt3}\)
4. \(\frac{\sqrt5}{\pi}\)

Subtopic:  Simple Harmonic Motion |
 77%
From NCERT
NEET - 2017
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A pendulum is hung from the roof of a sufficiently high building and is moving freely to and fro like a simple harmonic oscillator. The acceleration of the bob of the pendulum is 20 m/s2 at a distance of 5 m from the mean position. The time period of oscillation is:

1. 2π s 2. π s
3. 2 s 4. 1 s
Subtopic:  Angular SHM |
 85%
From NCERT
NEET - 2018
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A particle is executing a simple harmonic motion. Its maximum acceleration is α and maximum velocity is β. Then its time period of vibration will be:

1. \(\frac {\beta^2}{\alpha^2}\) 2. \(\frac {\beta}{\alpha}\)
3. \(\frac {\beta^2}{\alpha}\) 4. \(\frac {2\pi \beta}{\alpha}\)

Subtopic:  Simple Harmonic Motion |
 84%
From NCERT
NEET - 2015
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When two displacements are represented by \(y_1 = a \text{sin}(\omega t)\) and \(y_2 = b\text{cos}(\omega t)\) are superimposed, then the motion is:

1. not simple harmonic.
2. simple harmonic with amplitude \(\frac{a}{b}\).
3. simple harmonic with amplitude \(\sqrt{a^2+b^{2}}.\)
4. simple harmonic with amplitude \(\frac{a+b}{2}\).
Subtopic:  Simple Harmonic Motion |
 92%
From NCERT
NEET - 2015
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A particle is executing SHM along a straight line. Its velocities at distances \(x_1\) and \(x_2\) from the mean position are \(v_1\) and \(v_2\), respectively. Its time period is:

1. \(2 \pi \sqrt{\dfrac{x_{1}^{2}+x_{2}^{2}}{v_{1}^{2}+v_{2}^{2}}}~\) 2. \(2 \pi \sqrt{\dfrac{{x}_{2}^{2}-{x}_{1}^{2}}{{v}_{1}^{2}-{v}_{2}^{2}}}\)
3. \(2 \pi \sqrt{\dfrac{v_{1}^{2}+v_{2}^{2}}{x_{1}^{2}+x_{2}^{2}}}\) 4. \(2 \pi \sqrt{\dfrac{v_{1}^{2}-v_{2}^{2}}{x_{1}^{2}-x_{2}^{2}}}\)
Subtopic:  Simple Harmonic Motion |
 74%
From NCERT
NEET - 2015
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The oscillation of a body on a smooth horizontal surface is represented by the equation, \(X=A \text{cos}(\omega t)\),
where \(X=\) displacement at time \(t,\) \(\omega=\) frequency of oscillation.
Which one of the following graphs correctly shows the variation of acceleration, \(a\) with time, \(t?\)
(\(T=\) time period) \(a~~O~~T~~t~~\)

1. 2.
3. 4.

Subtopic:  Simple Harmonic Motion |
 66%
From NCERT
AIPMT - 2014
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The damping force of an oscillator is directly proportional to the velocity. The units of the constant of proportionality are:
1. kg-msec-1
2. kg-msec-2
3. kg-sec-1
4. kg-sec

Subtopic:  Damped Oscillations (OLD NCERT) |
 71%
From NCERT
AIPMT - 2012
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