The ratio of wavelengths of the last line of Balmer series and the last line of Lyman series is:
(1) 2
(2) 1
(3) 4
(4) 0.05
Given the value of Rydberg constant is , the wave number of the last line of the Balmer series in hydrogen spectrum will be:
(a) (b)
(c) (d)
Considering the \(3^{rd}\) orbit of \(\mathrm{He}^{+}\) (Helium ion), using the non-relativistic approach, the speed of the electron in this orbit will be: (Given: \(Z=2, K = 9\times 10^{9}\), and Planck's constant, \(h= 6.6\times10^{-34}\) J-s)
1. \(2.92\times 10^{8}\) m/s
2. \(1.46\times 10^{6}\) m/s
3. \(0.73\times 10^{8}\) m/s
4. \(3.0\times 10^{8}\) m/s
Electron in hydrogen atom first jumps from third exicted state to second exicted state and then from second exicted to the first excited state. The ratio of the wavelengths emitted in the two cases is
(1) 7/5
(2) 27/20
(3) 27/5
(4) 20/7
An electron of a stationary hydrogen atom passes from the fifth energy level to the ground level. The velocity that the atom acquires as a result of photon emission will be:
(m is the mass of the hydrogen atom, \(R\) Rydberg constant and \(h\) Planck's constant)
1. | \(\dfrac{24 h R}{25 m}\) | 2. | \(\dfrac{25 h R}{24 m}\) |
3. | \(\dfrac{25 m}{24 h R}\) | 4. | \(\dfrac{24 m}{25 h R}\) |
The transition from the state n=3 to n=1
a hydrogen like atom results in ultraviolet
radiation. Infrared radiation will be obtained
in the transition from
(a)
(b)
(c)
(d)
The wavelength of the first line of Lyman series for hydrogen atom is equal to that of the second line of Balmer series for a hydrogen-like ion. The atomic number Z of hydrogen-like ion is:
(1) 4
(2) 1
(3) 2
(4) 3
An electron in the hydrogen atom jumps from nth excited state to the ground state. The wavelength so emitted illuminates a photosensitive material having work function 2.75 eV. If the stopping potential of the photo-electron is 10V, the value of n is
(1) 3
(2) 4
(3) 5
(4) 2